A proton is traveling horizontally to the right at 4.20×106 m/s. A) Find the magnitude of...

A proton is traveling horizontally to the right at 4.20×10⁶ m/s.

A) Find the magnitude of the weakest electric field that can bring the proton uniformly to rest over a distance of 3.50 cm. E=___ N/C

B) What is the direction of this electric field?

C) How much time does it take the proton to stop after entering the field? t=____ s

D) What minimum field magnitude would be needed to stop an electron under the conditions of part A? E=___ N/C

E) What is the direction of the field in part D?

Expert Solution

The concept used is of electric field and the force balance when electron , proton comes to rest , in case of proton direction of electric field is in the left direction and viceversa in electron.

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genius_generous answered 1 year ago

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