In: Statistics and Probability
36. Allied Corporation is trying to determine whether to purchase Machine A or B. It has leased the two machines for a month. A random sample of 5 employees has been taken. These employees have gone through a training session on both machines. Below you are given information on their productivity rate on both machines. (Let d = Machine A - Machine B.)Productivity Rate
| 
 Person  | 
 Machine A  | 
 Machine B  | 
| 
 1  | 
 47  | 
 52  | 
| 
 2  | 
 53  | 
 58  | 
| 
 3  | 
 50  | 
 47  | 
| 
 4  | 
 55  | 
 60  | 
| 
 5  | 
 45  | 
 53  | 
please explain and show all work --- do NOT use excel commands/excel to solve this problem
a. State the null and alternative hypotheses for a two-tailed test.
b. Find the mean and standard deviation for the difference.
c. Compute the test statistic.
d. Test the null hypothesis stated in Part a at the 10% level.
a)
Ho :   µd=   0
Ha :   µd ╪   0
b)
paired t test
| Sample #1 | Sample #2 | difference , Di =sample1-sample2 | (Di - Dbar)² | 
| 47 | 52 | -5 | 1 | 
| 53 | 58 | -5 | 1 | 
| 50 | 47 | 3 | 49 | 
| 55 | 60 | -5 | 1 | 
| 45 | 53 | -8 | 16 | 
| total | -20 | 68 | 
mean of difference ,    D̅ =ΣDi / n = -20/5 =
-4
std dev of difference , Sd =    √ [ (Di-Dbar)²/(n-1) =
√(68/4) =   4.1231
c)
std error , SE = Sd / √n =    4.1231   /
√   5   =   1.8439  
   
          
           
   
t-statistic = (D̅ - µd)/SE = (   -4  
-   0   ) /    1.8439  
=   -2.169
d)
α=0.10
Degree of freedom, DF=   n - 1 =    4
t-critical value , t* =    ±   2.132 [from t
table ]
since, test stat = -2.169 < -2.132, Reject null
hypothesis
conclusion: there is enough evidence to conclude that there is difference in productivity rate on both machines at significance level of 10%