Question

In: Statistics and Probability

248 259 268 272 277 280 282 283 285 285 286 289 290 292 294 295...

248
259
268
272
277
280
282
283
285
285
286
289
290
292
294
295
295
298
310
501

Because the mean is very sensitive to extreme​ values, it is not a resistant measure of center. By deleting some low values and high​ values, the trimmed mean is more resistant. To find the​ 10% trimmed mean for a data​ set, first arrange the data in​ order, then delete the bottom​ 10% of the values and delete the top​ 10% of the​ values, then calculate the mean of the remaining values. Use the axial loads​ (pounds) of aluminum cans listed below for cans that are 0.0111 in. thick. Identify any​ outliers, then compare the​ median, mean,​ 10% trimmed​ mean, and​ 20% trimmed mean.

Solutions

Expert Solution

The scatterplot for the untrimmed data is shown below,

The scatter plot shows that there is one potential outlier valued 501 pounds.

The mean of the data values is obtained using the formula,

1 248
2 259
3 268
4 272
5 277
6 280
7 282
8 283
9 285
10 285
11 286
12 289
13 290
14 292
15 294
16 295
17 295
18 298
19 310
20 501
Mean 294.45
Median 285.5

Since n = 20 (even), median is the average of two middle values,

10% trimmed

After sorting the data values and then removing 10% (20*10%=2) of the upper and 10% of the lower values, the mean is,

1 268
2 272
3 277
4 280
5 282
6 283
7 285
8 285
9 286
10 289
11 290
12 292
13 294
14 295
15 295
16 298
Mean 285.6875
Median 285.5

Since n = 16 (even), median is the average of two middle values,

20% trimmed

ABy removing 20% (20*20%=2) of the upper and 20% of the lower values, the mean is,

1 277
2 280
3 282
4 283
5 285
6 285
7 286
8 289
9 290
10 292
11 294
12 295
Mean 286.5
Median 285.5

Since n = 12 (even), median is the average of two middle values,

Comparing median, mean,​ 10% trimmed​ mean, and​ 20% trimmed mean

Mean Median
untrimmed 294.45 285.5
10% trimmed 285.6875 285.5
20% trimmed 286.5 285.5

The median for each data set is same. since median is middle value of the data set, it is calculated irrespective of the data values. Hence it will be unchanged

Since there is a potential outlier present in the untrimmed data set with highest value, the mean is larger compare to mean of trimmed data set (such that mean is calculate after removing the outlier in trimmed data).


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