Question

22% express an interest in seeing XYZ television show. KL Broadcasting Company ran commercials for this XYZ television show and conducted a survey afterwards. 1532 viewers who saw the commercials were sampled and 414 said that they would watch XYZ television show. What is the point estimate of the proportion of the audience that said they would watch the television show after seeing the commercials? At α=0.05, determine whether the intent to watch the television show significantly increased after seeing the television commercials. Formulate the appropriate hypothesis, compute the p-value, and state your conclusion.

Answer 1

Let p be the population proportion of viewers who express an interest XYZ television show after seeing the commercials.

In a random sample of 1532 viewers, 414 said that they would watch XYZ television show.

The point estimate of the proportion of the audience that they would watch the television show batter seeing the commercials is given by:

At 5% level of significance, we want to test whether the intent to watch the television show significantly increased after seeing the television commercials from 0.22.

The hypothesis testing problem is:

The test statistic is:

The p value is:

. By using Excel function:

=1-NORM.DIST(4.72,0,1,1)

Since p value is less than level of significance (0.05), we reject the null hypothesis.

Therefore we have enough evidence to support the claim that the intent to watch the television show significantly increased after seeing the television commercials.