In: Statistics and Probability
Studies show that massage therapy has a variety of health benefits. A sample of 46 typical one-hour massage therapy sessions showed an average charge of $70. The population standard deviation for a one-hour session is $5.63. Estimate with 92% confidence the average charge of all one-hour massage therapy sessions. (Round to 2 decimal places.)
Solution :
Given that,
Point estimate = sample mean =
= $70
Population standard deviation =
= $5.63
Sample size = n =46
At 92% confidence level the z is ,
= 1 - 92% = 1 - 0.92 = 0.08
/ 2 = 0.08/ 2 = 0.04
Z/2 = Z0.04 = 1.75
Margin of error = E = Z/2
* (
/n)
= 1.75 * (5.63 / 46
)
= 1.45
At 95% confidence interval estimate of the population mean
is,
- E <
<
+ E
70 -1.45 <
<70 + 1.45
( ,68.55 ,71.45)