In: Statistics and Probability
A researcher is interested to learn if there is a relationship between the level of interaction a women in her 20s has with her mother and her life satisfaction ranking. Below is a list of women who fit into each of four level of interaction. Conduct a One-Way ANOVA on the data to determine if a relationship exists.
| 
 No Interaction  | 
 Low Interaction  | 
 Moderate Interaction  | 
 High Interaction  | 
| 
 2  | 
 3  | 
 3  | 
 9  | 
| 
 4  | 
 3  | 
 10  | 
 10  | 
| 
 4  | 
 5  | 
 2  | 
 8  | 
| 
 4  | 
 1  | 
 1  | 
 5  | 
| 
 7  | 
 2  | 
 2  | 
 8  | 
| 
 8  | 
 2  | 
 3  | 
 4  | 
| 
 1  | 
 7  | 
 10  | 
 9  | 
| 
 1  | 
 8  | 
 8  | 
 4  | 
| 
 8  | 
 6  | 
 4  | 
 1  | 
| 
 4  | 
 5  | 
 3  | 
 8  | 
Here is the ANOVA report performed in Excel
| ANOVA - Single Factor | ||||||
| Alpha | 0.05 | |||||
| Groups | Count | Sum | Mean | Variance | ||
| Column 1 | 10 | 43 | 4.3 | 6.9 | ||
| Column 2 | 10 | 42 | 4.2 | 5.5111111111 | ||
| Column 3 | 10 | 46 | 4.6 | 11.6 | ||
| Column 4 | 10 | 66 | 6.6 | 8.4888888889 | ||
| Source of Variation | SS | df | MS | F | P-value | F critical | 
| Between Groups | 38.275 | 3 | 12.7583333333 | 1.5702564103 | 0.2134340383 | 2.8662655509 | 
| Within Groups | 292.5 | 36 | 8.125 | |||
| 
 Total  | 
Err:508 | 39 | 
According this ANOVA, since p-value = 0.21 which is less than alpha=0.05, hence the differences between the means is not significantly different. Hence we do not have enough evidence to reject the null- hypothesis.