In: Statistics and Probability
| 
 y  | 
 x  | 
 xy  | 
 xx  | 
 yy  | 
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 11.4  | 
 0  | 
 0  | 
 0  | 
 129.96  | 
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 11.9  | 
 1  | 
 11.9  | 
 1  | 
 141.61  | 
| 
 7.1  | 
 2  | 
 14.2  | 
 4  | 
 50.41  | 
| 
 14.2  | 
 3  | 
 42.6  | 
 9  | 
 201.64  | 
| 
 5.9  | 
 4  | 
 23.6  | 
 16  | 
 34.81  | 
| 
 6.1  | 
 5  | 
 30.5  | 
 25  | 
 37.21  | 
| 
 5.4  | 
 6  | 
 32.4  | 
 36  | 
 29.16  | 
| 
 3.1  | 
 7  | 
 21.7  | 
 49  | 
 9.61  | 
| 
 5.7  | 
 8  | 
 45.6  | 
 64  | 
 32.49  | 
| 
 4.4  | 
 9  | 
 39.6  | 
 81  | 
 19.36  | 
| 
 4  | 
 10  | 
 40  | 
 100  | 
 16  | 
| 
 2.8  | 
 11  | 
 30.8  | 
 121  | 
 7.84  | 
| 
 2.6  | 
 12  | 
 31.2  | 
 144  | 
 6.76  | 
| 
 2.4  | 
 13  | 
 31.2  | 
 169  | 
 5.76  | 
| 
 5.2  | 
 14  | 
 72.8  | 
 196  | 
 27.04  | 
| 
 2  | 
 15  | 
 30  | 
 225  | 
 4  | 
| 
 94.2  | 
 120  | 
 498.1  | 
 1240  | 
 753.66  | 
a. Use the Equation to estimate Y if X = 3.5 Y Estimate = ___________
b. What is the Correlation Coefficient and what does the value tell you about the correlation between X and Y?
c. What is the Coefficient of Determination and what does the value tell you about the correlation between X and Y?
d. Based on your graph, does the data appear to be linear? – give comments to support your answer.
Regression Equation: y = -0.6129x + 10.485
Insert a scatterplot and select any data point and right click --> add trend line. Seelt linear as a trend and also selet "Display an equation on chart" and display R-squared"

a. Use the Equation to estimate Y if X = 3.5
y = -0.6129x + 10.485
x = 3.5
y = -0.6129*35 + 10.485
y = -10.97
The estimation of predicted value of x = 3.5 is -10.97
b. What is the Correlation Coefficient and what does the value tell you about the correlation between X and Y?
r = -0.80 (Negative correlation)

c. What is the Coefficient of Determination and what does the value tell you about the correlation between X and Y?
Coefficient of Determination is nothing but R-squared
R-square value is alreeady there in the scatter plot snap shot
R-squared = 0.64
d. Based on your graph, does the data appear to be linear? – give comments to support your answer.
Yes the data appear to be negative linear between x and y variable.