In: Statistics and Probability
88.5 |
98.8 |
89.6 |
92.2 |
92.7 |
88.4 |
87.5 |
90.9 |
94.7 |
88.3 |
90.4 |
83.4 |
87.9 |
92.6 |
87.8 |
89.9 |
84.3 |
90.4 |
91.6 |
91.0 |
93.0 |
93.7 |
88.3 |
91.8 |
90.1 |
91.2 |
90.7 |
88.2 |
94.4 |
96.5 |
89.2 |
89.7 |
89.0 |
90.6 |
88.6 |
88.5 |
90.4 |
84.3 |
92.3 |
92.2 |
89.8 |
92.2 |
88.3 |
93.3 |
91.2 |
93.2 |
88.9 |
|
91.6 |
87.7 |
94.2 |
87.4 |
86.7 |
88.6 |
89.8 |
|
90.3 |
91.1 |
85.3 |
91.1 |
94.2 |
88.7 |
92.7 |
|
90.0 |
86.7 |
90.1 |
90.5 |
90.8 |
92.7 |
93.3 |
|
91.5 |
93.4 |
89.3 |
100.3 |
90.1 |
89.3 |
86.7 |
|
89.9 |
96.1 |
91.1 |
87.6 |
91.8 |
91.0 |
91.0 |
On Excel
Ans a ) the stem and leaf plot is
Stem-and-Leaf Display | ||||
Stem unit: | 1 | |||
Statistics | 83 | 4 | ||
Sample Size | 82 | 84 | 3 3 | |
Mean | 90.52561 | 85 | 3 | |
Median | 90.4 | 86 | 7 7 7 | |
Std. Deviation | 2.905202 | 87 | 4 5 6 7 8 9 | |
Minimum | 83.4 | 88 | 2 3 3 3 4 5 5 6 6 7 9 | |
Maximum | 100.3 | 89 | 0 2 3 3 6 7 8 8 9 9 | |
90 | 0 1 1 1 3 4 4 4 5 6 7 8 9 | |||
91 | 0 0 0 1 1 1 2 2 5 6 6 8 8 | |||
92 | 2 2 2 3 6 7 7 7 | |||
93 | 0 2 3 3 4 7 | |||
94 | 2 2 4 7 | |||
95 | ||||
96 | 1 5 | |||
97 | ||||
98 | 8 | |||
99 | ||||
100 | 3 |
using minitab>stat>basic stat>descriptive stat
we have
Descriptive Statistics: data
Variable Mean StDev Variance Q1 Median Q3 Mode
data 90.526 2.905 8.440 88.575 90.400 92.200 90.1
the sample quartiles are Q1,Q2,and Q3 are 88.575 90.400 and 92.200 respectively
Ans b ) sample median = 90.4
mode= 90.1
mean=90.526
variance = 8.44
standard deviation. =2.905
Ans c ) using excel
histogram is
the shape is approximately normally distributed