In: Statistics and Probability
Consider the data in the table collected from three independent populations. |
Sample 1 |
Sample 2 |
Sample 3 |
||
---|---|---|---|---|---|
33 |
11 |
88 |
|||
a) Calculate the total sum of squares (SST) and partition the SST into its two components, the sum of squares between (SSB) and the sum of squares within (SSW). |
66 |
33 |
22 |
||
99 |
88 |
33 |
|||
1111 |
b) Use these values to construct a one-way ANOVA table.
c) Using
alphaαequals=0.100.10,
what conclusions can be made concerning the population means?
LOADING...
Click the icon to view a table of critical F-scores for
alphaαequals=0.100.10.
a) Determine the values.
SSTequals=nothing
(Type an integer or a decimal.)
SSBequals=nothing
(Type an integer or a decimal.)
SSWequals=nothing
(Type an integer or a decimal.)
b) Complete the one-way ANOVA table below.
Source |
Sum of Squares |
Degrees of Freedom |
Mean Sum of Squares |
F |
---|---|---|---|---|
Between |
nothing |
nothing |
nothing |
nothing |
Within |
nothing |
nothing |
nothing |
|
Total |
nothing |
nothing |
(Type integers or decimals. Round to three decimal places as needed.)
c) Let
mu 1μ1,
mu 2μ2,
and
mu 3μ3
be the population means of samples 1, 2, and 3, respectively. What are the correct hypotheses for a one-way ANOVA test?
A.
Upper H 0H0:
mu 1μ1equals=mu 2μ2equals=mu 3μ3
Upper H 1H1:
mu 1μ1not equals≠mu 2μ2not equals≠mu 3μ3
B.
Upper H 0H0:
mu 1μ1not equals≠mu 2μ2not equals≠mu 3μ3
Upper H 1H1:
Not all the means are equal.
C.
Upper H 0H0:
mu 1μ1not equals≠mu 2μ2not equals≠mu 3μ3
Upper H 1H1:
mu 1μ1equals=mu 2μ2equals=mu 3μ3
D.
Upper H 0H0:
mu 1μ1equals=mu 2μ2equals=mu 3μ3
Upper H 1H1:
Not all the means are equal.What is the critical F-score,
Upper F Subscript alphaFα?
Upper F Subscript alphaFαequals=nothing
(Round to three decimal places as needed.)
What is the correct conclusion about the population means?
Since the F-statistic
▼
falls
does not fall
in the rejection region,
▼
do not reject
reject
Upper H 0H0.
The data
▼
do not provide
provide
sufficient evidence to conclude that the population means are not all the same.
Click to select your answer(s).
Applying ANOVA:
a)
SST =106.4
SSB=8.40
SSW=98
b)
Source | SS | df | MS | F |
Between | 8.40 | 2 | 4.200 | 0.300 |
Within | 98.00 | 7 | 14.000 | |
Total | 106.40 | 9 |
c)
H0: μ1 = μ2 = μ3 |
H1: not all the means are equal |
critical F-score =Falpha =3.257
Since the F-statistic does not fall in the rejection region, , do not reject Ho
The data do not provide sufficient evidence to conclude that the population means are not all the same.