In: Chemistry
consider a hypothetical case in which the charge on a proton is twice that of an electron . Using this hypothetical case , and the fact that atoms maintain a charge of 0 , how many protons , neutrons , and electrons would a potassium -39 atom contain ?
Charge on a proton is twice that of an electron menas atom lost two electrons.
Atomic number of Potassium(K) = 19 and it has dipositive charge.
Number of protons = 19
number of electrons = 17
number of neutrons = mass number - atomic number
= 39 - 19
= 20