Question

In: Statistics and Probability

According to a government energy agency, the mean monthly household electricity bill in the United States...

According to a government energy agency, the mean monthly household electricity bill in the United States in 2011 was $109.54. Assume the amounts are normally distributed with standard deviation $25.00. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of bills are greater than $132?

(b) What proportion of bills are between $90 and $145?

(c) What is the probability that a randomly selected household had a monthly bill less than

$129? Round the answers to at least four decimal places.

Solutions

Expert Solution

Let "X" be the mean monthly household electricity bill in the United States in 2011

Refer Standard normal table/Z-table to find the probability or use excel formula "=NORM.S.DIST(0.8984, TRUE)" to find the probability.

The proportion of bills are greater than $132 is

-------------------------------------------------------------------------------------------------------

Refer Standard normal table/Z-table to find the probability or use excel formula "=NORM.S.DIST(1.4184, TRUE)" & "=NORM.S.DIST(-0.7816, TRUE)" to find the probability.

The proportion of bills are between $90 and $145 is

-------------------------------------------------------------------------------------------------------

Refer Standard normal table/Z-table to find the probability or use excel formula "=NORM.S.DIST(0.7784, TRUE)" to find the probability.

The probability that a randomly selected household had a monthly bill less than $129 is

orchestra answered 1 year ago
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