In: Chemistry
BIOCHEM LAB: You measured the total protein in a sample of purified protein via the Bradford technique and find you have purified 1,000 mg in 1,000 ml total volume. You also measured the activity of this protein and found it to be 301 U. What is the specific activity (in U/mg) for this enzyme?
Solution :-
Mass of protein purified = 1000 mg
Measured activity = 301 U
Specific activity in U/mg = ?
Lets use the given data to calculate the specific activity
Specific activity = measured activity / mass of protein
= 301 U / 1000 mg
= 0.301 U/mg
Therefore specific activity is 0.301 U/mg