In: Statistics and Probability
I hope tye die are rolled simultaneously and you want the proibbility that the Sum of the tow dice will show up your required events.
Let, A: the event that sum of the two numbers apperaed is an even number.
B: the sum of the two numbers appeared is greater than 10.
W have to find P[A or B] = P[]
By theorem of total probability we know,
Now ,
P[A] = probability that the sum of the apperaed number is an even number.
= probability that either both numbers are odd or both numbers are even
= [Because there are 3 odd and 3 even numbers in a dice ,
=1/2 So probability of a dice showing and odd number = 1/2 and thus 1/4 for two die ]
And P[B] = probability that a score of greater than 10 has apperaed
= P[Sum is either 11 or 12]
Now, total possble combination = (66) = 36 . [ such as {1,2},{1,3}......{2,1}.....{6,6}]
Out of which , score can be 11 in two cases : {5,6} and {6,5}
and 12 can appear in only one way : {6,6}
So total 3 cases favourable to event B .
Hence P[B] = 3/36 = 1/12
and P[A B] = P[The score is greater than 10 and an even number]
= P[The score is 12]
= 1/36 [Calculated earlier].
So finally
If you have doubts, or need explanation with different approach, let me know below, I will help you . Thank You.
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