In: Statistics and Probability
Based on an online survey done recently, the company asked a variety of questions regarding internet and email practices of a randomly selected sample size of 750 people aged 18 to 25 and 250 people that are over 65 years of age. In response to the question about whether the person has ever clicked on a link in an unsolicited email to get more information, 32% of the young people and 25% of the older folks said yes. Are these two groups equally likely to clinic on a link in an unsolicited email? In other words, does one group practice ‘safe clicking’ more than the other? Use a 95% confidence level. Report a p-value. Is this a weak or strong conclusion?
Sol:
Ho:p1=p2
Ha:p1 p2
alpha=0.05
z=p1^-p2^/sqrt(pbar(1-pbar)*(1/n1+1/n2)
x1=p1*n1=0.32*750=240
x2=p2*n2=0.25*250= 62.5
pbar=x1+x2/n1+n2
=240+62.5/750+250
=302.5/1000
=0.3025
z=(0.32-0.25)/sqrt(0.3025*(1-0.3025)*(1/750+1/250))
z= 2.086719
p value in excel
2*left tail
left tail prob==NORM.S.DIST( -2.086719,TRUE)=0.018456771
=2*0.018456771=
0.036913543
p value=0.036913543
p<0.05
Reject Ho
Accept Ha
Conclusion:
There is no suffcient statistical evidence at 5% level of significance to conlcude that e two groups equally likely to clinic on a link in an unsolicited email.
In other words, does one group practice ‘safe clicking’ more than the other