In: Operations Management
Janice Heller's company wants to establish an assembly line to manufacture its new product, the universal remote. Janice's goal is to produce 60 remotes per hour. Tasks, task times, and immediate predecessors are as follows: Task Time (sec) immediate predecessors Task Time (sec) immediate predecessors A 40 - F 25 C B 30 A G 15 C C 50 A H 20 D, E D 40 B I 18 F, G E 6 B J 30 H, I a. What is the cycle time? [ Select ] b. What is the theoretical number of stations? [ Select ] c. Balance the line using the longest operating time rule: What station should task G be assigned to? [ Select ] . What station should task C be assigned to? [ Select ] d. Based on the actual grouping and calculated cycle time, how many actual stations were needed to balance the line? [ Select ] e. Based on your answer to (d.), what is the efficiency and idle time? [ Select ] f. Can the efficiency of this line be improved? no improvement can be made . If so/not, what is the improved Cycle Time, Efficiency, and Idle Time? [ Select ]
please show every single step
a.Cycle time = 1 / 60 units pe hour = (1/60) hours = 60 seconds
b.Sum of all task times = 40+30+50+40+6+25+15+20+18+30 = 274 seconds
So, the theoretical minimum number of stations = 274 / cycle time = 274 / 60 = 4.6 or 5
Station | Remaining time | Eligibles | Was fit | Assigned time | Time remains | Idle time | Idle time (based on improved cycle time) |
1 | 60 | A | A | 40 | 20 | ||
20 | B, C | - | - | 20 | 20 | 15 | |
2 | 60 | B, C | C | 50 | 10 | ||
10 | B, F, G | - | - | 10 | 10 | 5 | |
3 | 60 | B, F, G | B | 30 | 30 | ||
30 | D, E, F, G | F | 25 | 5 | |||
5 | D, E, G | - | - | 5 | 5 | 0 | |
4 | 60 | D, E, G | D | 40 | 20 | ||
20 | E, G | G | 15 | 5 | |||
5 | E, I | - | - | 5 | 5 | 0 | |
5 | 60 | E, I | I | 18 | 42 | ||
42 | E | E | 6 | 36 | |||
36 | H | H | 20 | 16 | |||
16 | J | - | - | 16 | 16 | 11 | |
6 | 60 | J | J | 30 | 30 | 30 | 25 |
Totals | 274 | 86 | 56 | ||||
c.G is assigned to Station-4
d.Actual number of stations = 6
e.Efficiency = Sum of the task times / (No. of stations * cycle time) = 274 / (6*60) = 76.1%
Idle time = 86 seconds
f.The cycle time can be improved to the cycle time of the bottleneck (Station3 and 4) i.e. up to 55 seconds.
Efficiency = Sum of the task times / (No. of stations * improved cycle time) = 274 / (6*55) = 83%
Idle time = 56 seconds