In: Statistics and Probability
Which is an INCORRECT statement regarding the following cross-tabulation table about gender and diagnosis of 20 participants of study A?
Female | Male | Total | |
Depression Only | 2 | 2 | 4 |
16.6% | 25% | 20% | |
Anxiety Only | 6 | 6 | 12 |
50% | 75% | 60% | |
Depression & Anxiety | 4 | 0 | 4 |
33.3% | 0% | 20% | |
Total | 12 | 8 | 20 |
Group of answer choices
Approx. 16.6% of the female participants have depression only.
Among the participants who have anxiety only, 75% are male.
There are 12 participants who have anxiety only.
There is no male participant has both depression and anxiety.
40% of the entire study participants are male.
Solution:
Given:
Female | Male | Total | |
---|---|---|---|
Depression Only | 2 | 2 | 4 |
16.6% | 25% | 20% | |
Anxiety Only | 6 | 6 | 12 |
50% | 75% | 60% | |
Depression & Anxiety | 4 | 0 | 4 |
33.3% | 0% | 20% | |
Total | 12 | 8 | 20 |
We have to determine an INCORRECT statement regarding the cross-tabulation table about gender and diagnosis of 20 participants of study A.
First option: Approx. 16.6% of the female participants have depression only.
From table we can see there are 12 female and out of which 2 female participants have depression only.
Thus P( female participants have depression only) = 2/12 = 0.166 = 16.6%
Thus this is correct statement.
Second option: Among the participants who have anxiety only, 75% are male.
From table we can see, there are total 12 participants who have anxiety only and out of these 12 people, we have 6 male and 6 male , so percentage of male out of the participants who have anxiety only should be 6/12 = 0.5 = 50%
Thus this is an INCORRECT statement.
Third option: There are 12 participants who have anxiety only.
This is correct statement , since there are total 12 participants who have anxiety only.
Fourth option: There is no male participant has both depression and anxiety.
Correct, since count for both depression and anxiety and Male is 0.
Fifth option: 40% of the entire study participants are male.
We have total male = 8 and total participants = 20
thus percentage of male = 8 / 20 = 0.4 = 40%
Thus this is correct statement.