In: Statistics and Probability
A national health organization warns that 30% of middle school students nation wide have been drunk. A local health agency randomly surveys 100 students and only 25 report having been drunk. Construct an appropriate 80% confidence interval.
A. 0.25
B. 0.0555
C. 0.1946 to 0.3055
D. 0.1651 to 0.3349
Please show work and exaplain why. Thank you!
Solution : Given that, n = 100 x = 25
1 - At 80% confidence level the z is ,
Z Margin of error = E = Z = 1.282 * ( = 0.0555 A 80 % confidence interval for population proportion p is ,
0.250 - 0.0555 < p < 0.250 + 0.0555 0.1945< p < 0.3055 Option B) is correct. |