A
wine at room temperature of 75 ℉ is chilled on ice (32 ℉). If it...
A
wine at room temperature of 75 ℉ is chilled on ice (32 ℉). If it
takes 20 minutes for the wine to cool to 60 ℉, how long will it
take for the wine to reach 54 ℉?
Solutions
Expert Solution
Where T=T(t) is the temperature of the object at time t.
Then the time takes to the wine to cool to 54°F ≈ 31.32
minutes.
A volume of 80.0 mL of H2O is initially at room temperature
(22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water.
If the final temperature of the system is 21.50 ∘C , what is the
mass of the steel bar? Use the following values: specific heat of
water = 4.18 J/(g⋅∘C) specific heat of steel = 0.452 J/(g⋅∘C)
If we want to only use frozen water (ice) and room temperature
water (room temperature water of four times the mass of the ice),
write out the various forms of heat transfer that will occur
between frozen water and room temperature water, when the come into
contact.
Hint: There will be one term of heat transfer from the room
temperature water, and three terms of heat transfer in the ice/cold
water.
100. mL of H2O is initially at room temperature (22.0∘C). A
chilled steel rod at 2.0∘C is placed in the water. If the final
temperature of the system is 21.1 ∘C, what is the mass of the steel
bar? Specific heat of water = 4.18 J/g⋅∘C Specific heat of steel =
0.452 J/g⋅∘C Express your answer numerically, in grams, to one
significant figure.
A bottle of white wine at room temperature (68°F) is placed in a
refrigerator at 4 p.m. Its temperature after t hr is changing at
the rate of −18e^−0.6t °F/hr. By how many degrees will the
temperature of the wine have dropped by 10 p.m.? (Round your answer
to one decimal place.)
What will the temperature of the wine be at 10 p.m.? (Round your
answer to one decimal place.)
30 grams of ice at -5 Celsius melt while being left at room
temperature of 28 Celsius. After melting its temperature rises to
28 Celsius. Determine the total change of entropy of the
environment.
[Cice = .5 cal/g.C, Lf = 79.6 cal/gram] 1 calorie = 4.184 J
30 grams of ice at -5 Celsius melt while being left at room
temperature of 28 Celsius. After melting its temperature
rises to 28 Celsius. Determine the total change of
entropy of the ice.
[Cice = .5 cal/g.C, Lf = 79.6 cal/gram] 1
calorie = 4.184 J
Group of answer choices
a) 53.11 J/K
b) 34.68 J/K
c) 38.27 J/K
d) 44.22 J/K
e) 49.97 J/K
A mug of beer chilled to 36 degrees, if left in a 72-degree
room, will warm to a temperature of
T(t) = 72 −
36e−3.5t
degrees in t hours.
(a) Find T(0.35) and
T'(0.35).
(Round your answers to one decimal place.)
T(0.35)
=
°
T'(0.35)
=
°
Interpret your answers.
After 21 minutes, the temperature of the beer
is degrees and is increasing at the rate
of degrees per hour.
(b) Find T(1) and
T'(1).
(Round your answers to one decimal place.)...
Temperature (x)
65
70
75
80
85
90
95
100
105
Number of ice cream cones sold per hour (y)
8
10
11
13
12
16
19
22
23
Calculate the linear correlation coefficient r, for
temperature (x) and number of ice cream cones sold per
hour (y). (round to 3 decimal place)
Is there a linear relation between the two variables x, and y?
If yes, indicate if the relationship is positive or negative. (Hint
: use the Critical...
A wine shop wants to serve its white wine at a mean temperature
of 50 degrees. In a sample of 36 glasses of wine, the mean was
found to be 53 with a standard deviation of 3. The wine shop is
interested to see if the evidence indicates that the wine shop is
not meeting its temperature standard.
(a) Using a significance level of α=0.05, perform a two-tailed
hypothesis test to determine if the wine shop is not meeting its...
Boil water in a bowl and cool in a room. The air temperature in
the room is increasing linearly according to the function Ta (t) =
22 + 0.015t (t in minutes, T in ° C). Assume that Newton's Law of
Cooling is satisfied: the rate of change of water temperature is
proportional to the difference between the temperature of the water
and the temperature of the environment. We take the water
temperature after 8 minutes and find that it...