Question

In: Chemistry

Circle all of the following solutions that are isotonic with red blood cells (0.30 osmol) ?...

Circle all of the following solutions that are isotonic with red blood cells (0.30 osmol) ?

0.30 M NaCl 0.30M C6H12O6 0.10 M NaCL 0.10 M Na2CO3

Solutions

Expert Solution

Correct answers: 0.30 M C6H12O6

                            0.10 M Na2CO3

Osmolarity = n x m

where n = number of particles into which the molecules dissociates. For glucose (C6H12O6), n = 1. For NaCl, n=2. For Na2CO3, n=3.

m = molarity of the solution

Therefore, for 0.30 M glucose

osmolarity = 1 x 0.30 = 0.30 osmol

For 0.30 M NaCl, osmolarity = 2 x 0.30 = 0.60 osmol

For 0.10 M Na2CO3, osmolarity = 3 x 0.10 = 0.30 osmol

For 0.10 M NaCl, osmolarity = 2 x 0.10 = 0.20 osmol

Isotonic means having same osmotic pressure. Therefore 0.30 M glucose and 0.10 M Na2CO3 are isotonic with red blood cells (0.30 osmol)


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