In: Chemistry
A voltaic cell is constructed using solutions of NaHSO4, H2SO3, and MnSO4 with suitable electrodes. The relevant half reactions are:
HSO4- (aq) + 3H+ (aq) +2e- --> H2SO3(aq) + H2O (E0= 0.17v)
Mn+2(aq) + 2e- --> Mn(s) (E0= -1.18v)
A. Write the equation for the overall cell reaction and calculate the cell potential at standard conditions.
B. Calculate the cell potential if the [H+] is changed to pH=1.
C. Predict the qualitative effect (increase, decrease,no change) and order of magnitude (significant,minimal) on the cell potential if a solution of Ba(NO3)2 is added to both cell compartments. Explain your prediction.
BaSO3 Ksp= 8.3 x 10-7
BaSO4 Ksp= 1.2 x 10-10
HSO4- (aq) + 3H+ (aq) +2e- --> H2SO3(aq) + H2O (E0= 0.17v)
Mn+2(aq) + 2e- --> Mn(s) (E0= -1.18v)
Mn(s) ------------------------> Mn^2+ (aq) + 2e^- E0 = 1.18v
HSO4- (aq) + 3H+ (aq) +2e- --> H2SO3(aq) + H2O (E0= 0.17v)
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Mn(s) +HSO4- (aq) + 3H+ (aq) --> Mn^2+(aq) +H2SO3(aq) + H2O E0cell = 1.35v
B. PH = 1
-log[H+] = 1
[H+] = 10^-1M