A voltaic cell is constructed using solutions of NaHSO4, H2SO3, and MnSO4 with suitable electrodes. The...

A voltaic cell is constructed using solutions of NaHSO₄, H₂SO₃, and MnSO₄ with suitable electrodes. The relevant half reactions are:

HSO₄^- (aq) + 3H⁺ (aq) +2e^- --> H₂SO₃(aq) + H₂O (E₀= 0.17v)

Mn⁺²(aq) + 2e^- --> Mn(s) (E₀= -1.18v)

A. Write the equation for the overall cell reaction and calculate the cell potential at standard conditions.

B. Calculate the cell potential if the [H⁺] is changed to pH=1.

C. Predict the qualitative effect (increase, decrease,no change) and order of magnitude (significant,minimal) on the cell potential if a solution of Ba(NO₃)₂ is added to both cell compartments. Explain your prediction.

BaSO₃ K_sp= 8.3 x 10^-7

BaSO₄ Ksp= 1.2 x 10^-10

Solutions

Expert Solution

HSO₄^- (aq) + 3H⁺ (aq) +2e^- --> H₂SO₃(aq) + H₂O (E₀= 0.17v)

Mn⁺²(aq) + 2e^- --> Mn(s) (E₀= -1.18v)

Mn(s) ------------------------> Mn^2+ (aq) + 2e^- E0 = 1.18v

HSO₄^- (aq) + 3H⁺ (aq) +2e^- --> H₂SO₃(aq) + H₂O (E₀= 0.17v)

--------------------------------------------------------------------------------------------------

Mn(s) +HSO₄^- (aq) + 3H⁺ (aq) --> Mn^2+(aq) +H₂SO₃(aq) + H₂O E0cell = 1.35v

B. PH = 1

-log[H+] = 1

[H+] = 10^-1M

queen_honey_blossom answered 1 year ago

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