Question

In: Statistics and Probability

statistics and probability questions, solve clearly, show steps and in 30 minutes for thumbs up vote...

statistics and probability questions, solve clearly, show steps and in 30 minutes for thumbs up vote

A government report on remuneration for university administrators in Canada lists average salaries for various executive roles. The total annual salary for university presidents is listed as $500,000. To test this reported figure, at LOC = 95%, a random sample of 16 Canadian university presidents’ total annual salaries was collected. The raw data is below (in $/year):
618,000, 464,000, 686,000, 500,000, 746,000, 704,000, 596,000, 629,000,
523,000, 756,000, 561,000, 608,000, 691,000, 663,000, 529,000, 442,000.
a) Find the mean and standard deviation using a spreadsheet.
b) Assess the government report’s claim, using the critical-value method.
c) Use the p-value method to determine if there are any commonly-used LOC values for which the conclusion would be opposite to your answer from Part (a).

Solutions

Expert Solution

a)

b) Now we will conduct T test for testing the mean.

Since the null hypothesis is rejected we have evidence that government report’s claim that the total annual salary for university presidents is different than $500,000

c) Using the P-value approach: The p-value is p = 0.0005, and since p = 0.0005<0.05, it is concluded that the null hypothesis is rejected.

Commonly the least accepted LOC is 99% that is .

Hence there are none commonly used LOC values for which the conclusion would be opposite to your answer.

For Answer to be opposite the


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