Questions
1. To compute a student's Grade Point Average (GPA) for a term, the student's grades for...

1. To compute a student's Grade Point Average (GPA) for a term, the student's grades for each course are weighted by the number of credits for the course. Suppose a student had these grades:
4.0 in a 5 credit Math course
2.1 in a 2 credit Music course
2.8 in a 5 credit Chemistry course
3.0 in a 4 credit Journalism course
What is the student's GPA for that term? Round to two decimal places. Student's GPA =

2.A set of exam scores is normally distributed with a mean = 80 and standard deviation = 6.
Use the Empirical Rule to complete the following sentences.

68% of the scores are between ____ and _____ .

95% of the scores are between _____ and _____ .

99.7% of the scores are between ______ and _______

3. To compute a student's Grade Point Average (GPA) for a term, the student's grades for each course are weighted by the number of credits for the course. Suppose a student had these grades:

3.7 in a 5 credit Math course
2.4 in a 2 credit Music course
2.9 in a 4 credit Chemistry course
2.8 in a 4 credit Journalism course

What is the student's GPA for that term? Round to two decimal places.

Student's GPA =

In: Statistics and Probability

Your marketing department believes it has a new commercial that will increase the percent of people...

Your marketing department believes it has a new commercial that will increase the percent of people who plan on purchasing from one of your stores in the next month. You take a sample of people and before you show them the new commercial, ask them if they are planning on purchasing from one of your stores in the next month. You then show them the new commercial and follow up by asking again if they plan on purchasing from one of your stores in the next month. In your data analysis, you look at the difference of (post-commercial)-(pre-commercial). You want to test the claim that there is no difference between the pre and post commercial mean percentages, and do so at the α=0.02α=0.02 level.

You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain the following sample of data:

pre-commercial post-commercial
55.6 54.1
53.3 40.3
75.6 67
49 81.1
52.3 79
58.8 -44.7
67.7 78.7
63.5 -47
55.8 24.2
58.2 27.7
52.3 81.6
63.5 74.5
38.4 4.8
45.8 25.4
50.5 34.3
45.8 -21.9
48.7 7.8
51.3 9.3
65.6 94.9
62.9 37.4
63.7 24.9
47.2 26.8
60.7 23
68.8 93.1
56 52
  1. What is the test statistic for this sample?

    test statistic =  Round to 4 decimal places.
  2. What is the p-value for this sample? Round to 4 decimal places.

    p-value =
  3. The p-value is...
    • less than (or equal to) αα
    • greater than αα

  4. This test statistic leads to a decision to...
    • reject the null
    • accept the null
    • fail to reject the null

  5. As such, the final conclusion is that...
    • There is sufficient evidence to warrant rejection of the claim that the mean difference is not equal to 0.
    • There is not sufficient evidence to warrant rejection of the claim that the mean difference is not equal to 0.
    • The sample data support the claim that the mean difference is not equal to 0.
    • There is not sufficient sample evidence to support the claim that the mean difference is not equal to 0.

In: Statistics and Probability

4. Consider the following time series: Quarter Year 1 Year 2 Year 3 1 80 74...

4. Consider the following time series:

Quarter Year 1 Year 2 Year 3
1 80 74 65
2 69 61 51
3 48 50 43
4 68 71 82

a. Construct a time-series plot. What type of pattern exists in the data? Is there an indication of a seasonal pattern? (10 points)

b. Use multiple linear regression model with dummy variables as follows to develop an equation to account for seasonal effects in the data. Qtr1 = 1 if quarter 1, 0 else; Qtr2 = 1 if quarter 2, 0 else; Qtr3 = 1 if quarter 3, 0 else. (20 points)

c. Compute the quarterly forecasts for next year. (10 points)

In: Statistics and Probability

The average worker at Acme Labs produces 24 widgets per hour, with a standard deviation of...

The average worker at Acme Labs produces 24 widgets per hour, with a standard deviation of 8 widgets. You have invented a new production process, and you hypothesize that your new process will help workers produce more widgets per hour. After implementing the new production process, you take a sample of workers and measure how many widgets they produce per hour.

a) (2 points) What are the null and alternative hypotheses, in symbols?

b) (2 points) What are the null and alternative hypotheses, in words?

c) (5 points) The average number of widgets produced per hour by a sample of 80 workers turns out to be 26. Calculate the test statistic for this hypothesis test and find the p-value.

d) (4 points) At an alpha level of .05, do we have evidence that the new production process really increases productivity? Explain your reasoning.

In: Statistics and Probability

Find the Banzhaf power distribution of the following weighted voting system: [q : 15,13,8,6] a. If...

Find the Banzhaf power distribution of the following weighted voting system:

[q : 15,13,8,6]

a. If q=27

b. If q=22

c. If q=32

In: Statistics and Probability

I need answers for question 3 and 4. I believe I'm correct with question 1 and...

I need answers for question 3 and 4. I believe I'm correct with question 1 and 2 but not sure which could make question 3 and 4 incorrect.

  1. calculate descriptive statistics for the variable (Coin) where each of the thirty-five students in the sample flipped a coin 10 times. Round your answers to three decimal places and type the mean and the standard deviation in the grey area below.
    Coin
    7
    6
    4
    6
    4
    6
    4
    6
    4
    4
    3
    5
    5
    6
    3
    3
    5
    6
    3
    7
    5
    2
    6
    6
    6
    3
    3
    7
    2
    4
    6
    5
    6
    6
    7
  2. Mean: 4.885

    Standard deviation: 1.490

  3. List the probability value for each possibility in the binomial experiment calculated at the beginning of this lab, which was calculated with the probability of a success being ½. (Complete sentence not necessary; round your answers to three decimal places)

P(x=0)

P(x=6)

P(x=1)

P(x=7)

P(x=2)

P(x=8)

P(x=3)

P(x=9)

P(x=4)

P(x=10)

P(x=5)

4. Give the probability for the following based on the calculations in question 3 above, with the probability of a success being ½. (Complete sentence not necessary; round your answers to three decimal places)

P(x≥2)

P(x<0)

P(x>2)

P(x≤5)

P(5<x ≤7)

P(x<5 or x≥7)


In: Statistics and Probability

Range of ankle motion is a contributing factor to falls among the elderly. Suppose a team...

Range of ankle motion is a contributing factor to falls among the elderly. Suppose a team of researchers is studying how compression hosiery, typical shoes, and medical shoes affect range of ankle motion.

In particular, note the variables Barefoot and Footwear5 (FW5). Barefoot represents a subject's range of ankle motion (in degrees) while barefoot, and Footwear5 (FW5) represents their range of ankle motion (in degrees) while wearing compression hosiery and medical shoes.

Use this data and your preferred software to calculate the equation of the least-squares linear regression line to predict a subject's range of ankle motion while wearing compression hosiery and medical shoes, ?̂ y^ , based on their range of ankle motion while barefoot, ?x . Round your coefficients to two decimal places of precision.

?̂ y^ =

A physical therapist determines that her patient Jan has a range of ankle motion of 7.26°7.26° while barefoot. Predict Jan's range of ankle motion while wearing compression hosiery and medical shoes, ?̂ y^ . Round your answer to two decimal places.

?̂ =y^=

Suppose Jan's actual range of ankle motion while wearing compression hosiery and medical shoes is 9.79°9.79° . Use her predicted range of ankle motion to calculate the residual associated with this value. Round your answer to two decimal places.

residual=

In order to assess the linear regression equation's ability to predict range of ankle motion, the physical therapist reviewed a scatterplot of the researchers' sample data and calculated the correlation, ?=0.53r=0.53 .

Barefoot FW1 FW2 FW3 FW4 FW5
34.851 32.927 37.455 31.719 27.937 27.483
17.309 18.468 11.617 23.863 26.681 20.687
30.921 32.616 31.59 37.228 27.908 32.626
23.067 28.614 23.782 23.766 25.293 21.336
26.665 26.056 24.749 24.809 30.978 28.229
24.865 28.931 31.218 22.463 25.386 21.749
23.64 37.264 27.016 27.615 29.044 30.889
27.416 30.716 22.181 27.281 31.016 37.565
18.079 20.052 17.486 11.296 20.909 14.573
19.659 21.54 20.186 20.369 17.609 22.501
32.875 30.725 28.188 28.678 29.013 29.013
12.859 16.772 16.289 12.07 14.428 24.308
23.155 24.625 18.363 24.325 31.178 22.121
21.66 31.301 25.894 25.893 27.762 25.498
21.808 24.97 19.964 23.087 25.475 20.586
27.784 20.623 21.233 30.305 27.119 26.509
26.953 33.153 27.35 23.463 33.045 24.015
21.203 25.033 20.387 33.77 28.263 23.86
26.065 34.133 22.761 26.053 29.894 23.954
16.658 27.805 15.032 26.853 27.778 20.402
30.123 28.414 27.457 26.625 27.539 23.434
15.447 22.073 15.2 33.395 22.7 20.321
23.924 25.478 19.357 20.732 29.334 20.325
13.807 24.112 21.877 20.653 26.294 26.093
16.114 16.365 12.127 17.134 23.874 17.643
22.533 29.161 30.178 25.869 31.884 19.14
23.005 18.487 19.135 21.793 20.111 19.14

In: Statistics and Probability

Statistics for Criminology and Criminal Justice The probability of being acquitted in criminal court in Baltimore,...

Statistics for Criminology and Criminal Justice

The probability of being acquitted in criminal court in Baltimore, Maryland, is .40. You take a random sample of the past 10 criminal cases where the defendant had a public defender and find that there were seven acquittals and three convictions. What is the probability of observing seven or more acquittals out of 10 cases if the true probability of an acquittal is .40? By using an alpha of .05, test the null hypothesis (that the probability of an acquittal is .40 for defendants with public defenders), against the alternative hypothesis that it is greater than .40.

In: Statistics and Probability

You wish to test the following claim (HaHa) at a significance level of α=0.01α=0.01. Ho:μ1=μ2Ho:μ1=μ2 Ha:μ1≠μ2Ha:μ1≠μ2...

You wish to test the following claim (HaHa) at a significance level of α=0.01α=0.01.

Ho:μ1=μ2Ho:μ1=μ2
Ha:μ1≠μ2Ha:μ1≠μ2

You believe both populations are normally distributed, but you do not know the standard deviations for either. And you have no reason to believe the variances of the two populations are equal You obtain a sample of size n1=14n1=14 with a mean of ¯x1=79.7x¯1=79.7 and a standard deviation of s1=11.8s1=11.8 from the first population. You obtain a sample of size n2=15n2=15 with a mean of ¯x2=83.8x¯2=83.8 and a standard deviation of s2=19.1s2=19.1 from the second population.

  1. What is the test statistic for this sample?

    test statistic =  Round to 3 decimal places.
  2. What is the p-value for this sample? For this calculation, use .

    p-value =  Use Technology Round to 4 decimal places.
  3. The p-value is...
    • less than (or equal to) αα
    • greater than αα

  4. This test statistic leads to a decision to...
    • reject the null
    • accept the null
    • fail to reject the null

  5. As such, the final conclusion is that...
    • There is sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
    • There is not sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
    • The sample data support the claim that the first population mean is not equal to the second population mean.
    • There is not sufficient sample evidence to support the claim that the first population mean is not equal to the second population mean.
  6. Similarly, you now wish to test the following claim (HaHa) at a significance level of α=0.10α=0.10.

    Ho:μ1=μ2Ho:μ1=μ2
    Ha:μ1≠μ2Ha:μ1≠μ2

    You believe both populations are normally distributed, but you do not know the standard deviations for either. And you have no reason to believe the variances of the two populations are equal You obtain a sample of size n1=14n1=14 with a mean of ¯x1=59.9x¯1=59.9 and a standard deviation of s1=15.6s1=15.6 from the first population. You obtain a sample of size n2=10n2=10 with a mean of ¯x2=51.6x¯2=51.6 and a standard deviation of s2=13.4s2=13.4 from the second population.

  7. What is the test statistic for this sample?

    test statistic =  Round to 3 decimal places.
  8. What is the p-value for this sample? For this calculation, use .

    p-value =  Use Technology Round to 4 decimal places.
  9. The p-value is...
    • less than (or equal to) αα
    • greater than αα

  10. This test statistic leads to a decision to...
    • reject the null
    • accept the null
    • fail to reject the null

  11. As such, the final conclusion is that...
    • There is sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
    • There is not sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
    • The sample data support the claim that the first population mean is not equal to the second population mean.
    • There is not sufficient sample evidence to support the claim that the first population mean is not equal to the second population mean.

In: Statistics and Probability

The 2015 American Time Use Survey contains data on how many minutes of sleep per night...

The 2015 American Time Use Survey contains data on how many minutes of sleep per night an average college student gets. According to this survey, the minutes that college students sleep per night are right skewed with a mean of 529.9 minutes and standard deviation 135.6 minutes.

Suppose we take a random sample of size 20. What is the probability that the mean of the 20 times is greater than 538 minutes?

Answer --> It is not appropriate to calculate probabilities in this situation. (explain why, please)


Suppose we take a random sample of size 60. What is the probability that the mean of the 60 times is less than 479.4 minutes?

A. 0.0020

B. 0.9980

C. 0.3557

D. 0.6643

E. It is not appropriate to calculate probabilities in this situation.

In: Statistics and Probability

If you draw a card with a value of four or less from a standard deck...

If you draw a card with a value of four or less from a standard deck of cards, I will pay you $⁢134.  If not, you pay me $⁢37.  (Aces are considered the highest card in the deck.)

Step 2 of 2 :  

If you played this game 621 times how much would you expect to win or lose? Round your answer to two decimal places. Losses must be entered as negative.

In: Statistics and Probability

The amounts (in ounces) of juice in eight randomly selected juice bottles are: 15.3 15.3 15.7...

The amounts (in ounces) of juice in eight randomly selected juice bottles are:

15.3 15.3 15.7 15.7
15.3 15.9 15.3 15.9

Construct a 98% confidence interval for the mean amount of juice in all such bottles.

In: Statistics and Probability

Assume that adults have IQ scores that are normally distributed with a mean of 97.7 and...

Assume that adults have IQ scores that are normally distributed with a mean of 97.7 and a standard deviation 21.8

Find the first quartile Upper Q1, which is the IQ score separating the bottom​ 25% from the top​ 75%. (Hint: Draw a​ graph.)

The first quartile is ________. ​(Type an integer or decimal rounded to one decimal place as​ needed.)

In: Statistics and Probability

The manager of a cosmetics section of a large department store wants to determine whether newspaper...

The manager of a cosmetics section of a large department store wants to determine whether newspaper advertising affects sales.  She randomly selects 10 items currently in stock that are priced at their usual competitive value, and she records the quantity of each item sold for a one-week period.  Then, without changing their price, she places a large ad in the newspaper, advertising the 10 items.  Again, she records the quantity sold for a one-week period.  Her data are listed below:                                

Item

# Sold Before Ad

# Sold After Ad

1

18

24

2

3

7

3

16

19

4

23

23

5

15

5

6

7

11

7

13

12

8

16

12

9

20

25

10

14

20

Test whether placement of the ad resulted in a significant increase in sales, with an alpha of .05.

a. State the H0 and H1 hypotheses, in statistical notation, and identify the critical t value(s).

b. Calculate standard error and the observed t-statistic.  What is your decision regarding the null hypothesis?  Why?

c. State your results in nonstatistical terms.

d. State the type of t-test you used for problems A, B, and C, above, and explain why each test was the appropriate one to choose.

In: Statistics and Probability

A social psychologist claims to know how many casual friends are in the typical person's social...

A social psychologist claims to know how many casual friends are in the typical person's social network.  The psychologist states that the average number of casual friends is 11.  You question the validity of this researcher's claim and decide to conduct your own study.  You interview a random sample of people and determine for each the number of friends or social acquaintances they see or talk to at least once a year.  Your data are below:

16

4

6

11

16

4

8

7

8

3

10

6

9

21

14

12

9

11

Test if your results differ from the social psychologist's claim, with an alpha of .05.

a. State the H0 and H1 hypotheses, in statistical notation, and identify the critical t value(s).

b. Calculate standard error and the observed t-statistic.  What is your decision regarding the null hypothesis?  Why?

c. State your results in nonstatistical terms.

In: Statistics and Probability