Questions
Use R and perform following: Generate 1000 observations from an exponential distribution with mean 10. Generate...

Use R and perform following:


Generate 1000 observations from an exponential distribution with mean 10.
Generate 1000 observations from a central t-distribution with 8 degree of freedom.
Make a qqplot of observations in problem 1 versus quantiles generated from a t-distribution
with 8 degree of freedom. Can the t distribution be used to approximate data in part 1?Submit
the plot.
Repeat above part but submit a qqplot of the observations in 1 versus quantiles from an exponential
with mean 1. What is your conclusion?

In: Statistics and Probability

How do we check whether the data collected in a research project comes from a Normal...

How do we check whether the data collected in a research project comes from a Normal distribution?

In: Statistics and Probability

Briefly explain the difference between range, interquartile range, and standard deviation.

Briefly explain the difference between range, interquartile range, and standard deviation.

In: Statistics and Probability

bba year 2 business administration (marketing) Question: macro environmental forces effect all firms in the industry,...

bba year 2 business administration (marketing)
Question:
macro environmental forces effect all firms in the industry, influencing considerably the market opportunities and activities. The macro environment can be audited using the PEST or SLEPT analysis. explain the various aspects of this analysis. support your discussion with examples where possible.

In: Statistics and Probability

Discuss a management decision-making perspective for "concept of moving average and its use" with detailed examples.

Discuss a management decision-making perspective for "concept of moving average and its use" with detailed examples.

In: Statistics and Probability

In essay format, give a detailed explanation of linear regression, talking about what it is, its...

In essay format, give a detailed explanation of linear regression, talking about what it is, its origin, mathematical justification, and formulas that make up the method.
References

In: Statistics and Probability

What is the main reason for using covariance analysis in a randomized study?

What is the main reason for using covariance analysis in a randomized study?

In: Statistics and Probability

A head librarian supervises a number of libraries in a large county. He wants to know...

A head librarian supervises a number of libraries in a large county. He wants to know if full-time library workers and part-time library workers re-shelve books at the same rate. So, he checks the records of 45 full-time library workers and finds that they re-shelve an average of 166 books per hour with a standard deviation of 9.3 books per hour. The records of 45 part-time library show that they re-shelve an average of 159 books per hour with a standard deviation of 12.2 books per hour.

Using a level of significance of α=.01, is there enough evidence to indicate a difference in the mean number of books re-shelved by full-time workers compared to part-time workers?

please be detailed in telling how to locate the z= 1.645 and z= -1.645

In: Statistics and Probability

Based on historical data, your team knows what proportion of the company's orders come from Males...

Based on historical data, your team knows what proportion of the company's orders come from Males (and Females). However, your team would like to expand its sales so that men are more proportionately represented. By the end of this year, you think you would like your total proportion of sales to males to be at least 0.45. If you took a simple random sample of 57 current orders, what is the probability that the sample proportion of male customers is greater than 0.45? Note: You should carefully round any intermediate calculations to 4 decimal places to match wamap's approach and calculations. Answer = Incorrect (Enter your answer as a number accurate to 4 decimal places.)

Gender n Mean Variance Std. dev. Std. err. Median Range Min Max Q1 Q3
Female 1404 110.26788 12292.386 110.87103 2.958929 73.95 796.68 4 800.68 32.755 150.16
Male 923 108.90898 12695.331 112.67356 3.7086953 72.15 868.45 4.04 872.49 31.62 149.11

In: Statistics and Probability

Please show work (i.e. equations used) not just the final answer Use the data from the...

Please show work (i.e. equations used) not just the final answer

  1. Use the data from the Table to answer the questions below:

Population Statistics for a Hypothetical County

Measure

Number

Measure

Number

Total 1-year Population

200,000

Number of deaths of persons aged 55 years and older

850

Population of women 15-44 years of age

50,000

Number of deaths of among women aged 55 years and older

460

Population of women 55 years of age or older

55,000

Number one cause of death in the county is heart disease - deaths from heart disease

130

Number of live births

3,500

Number two cause of death in the county is from cancer - deaths from cancer

70

Number of fetal deaths

65

Number three cause of death in the county is from cerebrovascular accident (stroke)

60

Number of maternal deaths

8

Number four cause of death in the county is unintentional injuries

45

Total deaths

1,400

Number of deaths from cancer age 55 years and older

45

Number of infant deaths

90

Number of persons diagnosed heart disease

5,600

Number of deaths under 28 days old

5

Number of deaths from other causes

510

Number of deaths between 20 weeks gestation and 28 days old

10

Number of abortions

1,250

Source:  

Determine the following:

  1. Crude death rate
  2. Maternal mortality rate
  3. Infant mortality rate
  4. Neonatal mortality rate
  5. Abortion rate
  6. Fertility rate
  7. Age-specific mortality rate for women aged 55 years or older
  8. Cause-specific mortality rate for those who died from heart disease
  9. Cause specific mortality rate for those who died from stroke
  10. Proportional mortality ratio for cancer among persons ages 55 years or older

In: Statistics and Probability

A customer wants to estimate the average delivery time of a pizza from the local pizza...

A customer wants to estimate the average delivery time of a pizza from the local pizza parlor. Over the course of a few months, the customer orders 28 pizzas and records the delivery times. The average delivery time is 20.06 with a standard deviation of 5.271. If the customer estimates the time using a 95% confidence interval, what is the margin of error?

Question 1 options:

1)

2.0439

2)

1.6967

3)

0.9961

4)

0.6215

5)

2.0405

Question 2 (1 point)

You own a small storefront retail business and are interested in determining the average amount of money a typical customer spends per visit to your store. You take a random sample over the course of a month for 15 customers and find that the average dollar amount spent per transaction per customer is $86.485 with a standard deviation of $15.8647. Create a 99% confidence interval for the true average spent for all customers per transaction.

Question 2 options:

1)

( 74.291 , 98.679 )

2)

( 82.389 , 90.581 )

3)

( 83.508 , 89.462 )

4)

( -74.291 , 98.679 )

5)

( 74.413 , 98.557 )

Question 3 (1 point)

The owner of a local phone store wanted to determine how much customers are willing to spend on the purchase of a new phone. In a random sample of 9 phones purchased that day, the sample mean was $338.73 and the standard deviation was $19.7969. Calculate a 95% confidence interval to estimate the average price customers are willing to pay per phone.

Question 3 options:

1)

( -323.513 , 353.947 )

2)

( 336.424 , 341.036 )

3)

( 332.131 , 345.329 )

4)

( 323.513 , 353.947 )

5)

( 323.803 , 353.657 )

Question 4 (1 point)

Suppose you work for Fender Guitar Company and you are responsible for testing the integrity of a new formulation of guitar strings. To perform your analysis, you randomly select 40 'high E' strings and put them into a machine that simulates string plucking thousands of times per minute. You record the number of plucks each string takes before failure and compile a dataset. You find that the average number of plucks is 6,886.7 with a standard deviation of 117.85. A 99% confidence interval for the average number of plucks to failure is (6,836.2, 6,937.2). From the option listed below, what is the appropriate interpretation of this interval?

Question 4 options:

1)

We are 99% confident that the proportion of all 'high E' guitar strings fail with a rate between 6,836.2 and 6,937.2.

2)

We are 99% confident that the average number of plucks to failure for all 'high E' strings tested is between 6,836.2 and 6,937.2.

3)

We cannot determine the proper interpretation of this interval.

4)

We are 99% confident that the average number of plucks to failure for all 'high E' strings is between 6,836.2 and 6,937.2.

5)

We are certain that 99% of the average number of plucks to failure for all 'high E' strings will be between 6,836.2 and 6,937.2.

Question 5 (1 point)

The owner of a local golf course wants to determine the average age of the golfers that play on the course in relation to the average age in the area. According to the most recent census, the town has an average age of 23.44. In a random sample of 26 golfers that visited his course, the sample mean was 30.63 and the standard deviation was 8.771. Using this information, the owner calculated the confidence interval of (25.84, 35.42) with a confidence level of 99%. Which of the following statements is the best conclusion?

Question 5 options:

1)

We are 99% confident that the average age of all golfers that play on the golf course is greater than 23.44

2)

We are 99% confident that the average age of all golfers that play on the golf course is less than 23.44

3)

The average age of all golfers does not significantly differ from 23.44.

4)

The percentage of golfers with an age greater than 23.44 is 99%.

5)

We cannot determine the proper interpretation based on the information given.

Question 6 (1 point)

Researchers at a metals lab are testing a new alloy for use in high end electronics. The alloy is very expensive to make so their budget for testing is limited. The researchers need to estimate the average force required to bend a piece of the alloy to a 90 degree angle. From previous tests, the standard deviation is known to be 34.632 Newtons. In order to estimate the true mean within a margin of error of 9.703 Newtons with 99% confidence, how many samples would need to be tested?

Question 6 options:

1)

We do not have enough information to answer this question since we were not given the sample mean.

2)

95

3)

90

4)

84

5)

85

Question 7 (1 point)

A pharmaceutical company is testing a new drug to increase memorization ability. It takes a sample of individuals and splits them randomly into two groups. After the drug regimen is completed, all members of the study are given a test for memorization ability with higher scores representing a better ability to memorize. Those 28 participants on the drug had an average test score of 28.396 (SD = 4.142) while those 26 participants not on the drug had an average score of 40.736 (SD = 5.24). You use this information to create a 90% confidence interval for the difference in average test score. What is the margin of error? Assume the population standard deviations are equal.

Question 7 options:

1)

1.28060017

2)

1.662

3)

2.145

4)

1.67468915

5)

2.106

Question 8 (1 point)

In a consumer research study, several Meijer and Walmart stores were surveyed at random and the average basket price was recorded for each. It was found that the average basket price for 8 Meijer stores was $132.15 with a standard deviation of $24.701. 11 Walmart stores had an average basket price of $156.97 with a standard deviation of $19.049. Construct a 99% confidence interval for the difference between the true average basket prices (Meijer - Walmart). You can assume that the standard deviations of the two populations are statistically similar.

Question 8 options:

1)

(-50.62, 0.98)

2)

(-53.85, 4.21)

3)

(-34.84, -14.8)

4)

We only have the sample means, we need to know the population means in order to calculate a confidence interval.

5)

(-650.61, 600.97)

Question 9 (1 point)

Independent random samples are taken at a university to compare the average GPA of seniors to the average GPA of sophomores. Given a 95% confidence interval for the difference between the true average GPAs (seniors - sophomores) of (0, 1.13), what can you conclude?

Question 9 options:

1)

We are 95% confident that the difference between the two sample GPAs falls within the interval.

2)

We are 95% confident that the average GPA of seniors is greater than the average GPA of sophomores.

3)

There is no significant difference between the true average GPA for seniors and sophomores.

4)

We do not have enough information to make a conclusion.

5)

We are 95% confident that the average GPA of seniors is less than the average GPA of sophomores.

Question 10 (1 point)

The owner of a local golf course wants to estimate the difference between the average ages of males and females that play on the golf course. He randomly samples 24 men and 21 women that play on his course. He finds the average age of the men to be 37.722 with a standard deviation of 7.091. The average age of the women was 32.214 with a standard deviation of 5.243. He uses this information to calculate a 99% confidence interval for the difference in means, (0.436, 10.58). The best interpretation of this interval is which of the following statements?

Question 10 options:

1)

We are certain that the difference between the average age of all men and all women is between 0.436 and 10.58.

2)

We are 99% confident that the difference between the average age of the men and women surveyed is between 0.436 and 10.58

3)

We do not know the population means so we do not have enough information to make an interpretation.

4)

We are 99% sure that the average age difference between all males and females is between 0.436 and 10.58.

5)

We are 99% confident that the difference between the average age of all men and all women who play golf at the course is between 0.436 and 10.58

no need to show work

In: Statistics and Probability

A Sleep researcher coducts an experiment to determine whether a hypnotic drug called Drowson, Which is...

A Sleep researcher coducts an experiment to determine whether a hypnotic drug called Drowson, Which is advertised as a remedy for insomnia, Actually does promote sleep. In addition, the researcher is interested in whether a tolerance to the drug develops with chronic use. The design of the experiment is a 2 X 2 factorial independent groups design.
One of the variables is the concentration of Drowson. There are two levels: 1- zero concentration (placebo) and 2- the manufacturer’s minimum recommended dosage. The other variable concerns the previous use of Drowson. Again there are two levels: 1- Subjects with no previous use and 2- chronic users. Sixteen individuals with Sleep- onset insomnia (difficulty in falling a sleep) Who Have Had no previous use of Drowson Are randomly assigned to the two concentration conditions, such that there are eight subjects in each condition.
Sixteen chronic users of Drowson are also assigned randomly to the two conditions, eight subjects per condition. All subjects take their prescribed “medication” for 3 consecutive nights, and the Time To Fall asleep is recorded.

No previous use(Placebo):
45 53
48 58
62 55
70 64
No Previous use(Min. Recommended Dosage):
30 47
33 35
40 31
50 39

Chronic Users(Placebo):
47 68
52 64
55 58
62 59
Chronic users(Min. Recommended Dosage):
52 46
60 49
58 50
68 55

Test all the null hypotheses at both .05 and .01 level.

In: Statistics and Probability

The average price for a gallon of gasoline in the United States is $3.74 and in...

The average price for a gallon of gasoline in the United States is $3.74 and in Russia it is $3.4. Assume these averages are the population means in the two countries and that the probability distributions are normally distributed with a standard deviation of $0.25 in the United States and a standard deviation of $0.20 in Russia.

a. What is the probability that a randomly selected gas station in the United States charges less than $3.65 per gallon (to 4 decimals)?

b. What percentage of the gas stations in Russia charge less than $3.65 per gallon (to 2 decimals)?

c. What is the probability that a randomly selected gas station in Russia charged more than the mean price in the United States (to 4 decimals)?

In: Statistics and Probability

You wish to determine whether consumers have made substantial progress in reducing their credit card debt?...

You wish to determine whether consumers have made substantial progress in reducing their credit card debt? Based on a sample of 1000 consumers in September 2001, and another sample of 1000 customers in September 2006, the average credit card debt 2711 in 2001 as compared to 2814 in 2006. The standard deviation of each sample was approximately 976. Using a level of significance of 0.1,

a. What are the null and alternative hypothesis? (How do yo know)

b. What is the critical value? (Explain and show work)

c. Which minitab output is appropriate for this problem? (How do you know)

d. What is your managerial conclusion? (why)

In: Statistics and Probability

The posterior probabilities of four hypothesis h1,h2,h3,h4 are (0.2, 0.5,0.2, 0.1) respectively. A new training sample...

The posterior probabilities of four hypothesis h1,h2,h3,h4 are (0.2, 0.5,0.2, 0.1) respectively. A new training sample is classified +ve by h2 and h3, while h1 and h4 classify the same data instance as -ve. Find the classification with Bayes Optimal Classifier and Brute Force Classification?

In: Statistics and Probability