Protestant |
Catholic |
Jew |
None |
Other |
8 |
12 |
12 |
15 |
10 |
12 |
20 |
13 |
16 |
18 |
13 |
25 |
18 |
23 |
12 |
17 |
27 |
21 |
28 |
12 |
In: Statistics and Probability
Calculating the probability that in a class of 20 students, there are at least two with the same birthday.
(a) First, calculate the probability that each student has a different birthday as follows (round to four decimal places)
b) Explain briefly why the above probability is calculated that
way.
(c) Now note that the probability that there are at least two with
the same birthday is the complement of the above probability. What
is the probability that there are at least two with the same
birthday
In: Statistics and Probability
3. In the workbook on page 14, we solved the following
problem:
A new type of light bulb has been developed which is believed to
last longer than
ordinary light bulbs. To determine the average life of the new
light bulb, a random sample of
100 light bulbs was tested. The sample had a mean life of 1960
hours. Estimate the true mean
life of the new light bulb using a 97% confidence interval. State
your final conclusion using a
clear, complete sentence. Assume the population standard deviation
is 142 hours.
For the confidence interval we calculated in this workbook problem,
the confidence level
is 97%.
Using ZInterval on the calculator we found the 97% confidence
interval for the mean life
was 1929.2 to 1990.8 hours. Based on this sample, we are 97%
confident that the mean life
expectancy of all the new lightbulbs is between 1929.2 and 1990.8
hours.
The length of a confidence interval is (upper bound- lower bound).
For this
confidence interval, the length is (1990.8-1929.2) = 61.6
hours.
To find the Margin of Error, using the length of a confidence
interval, we use
EE = mmmmmmmmmmmm oooo eeeeeeeeee = llllnnnnnnnn oooo CCCC
22 . For this CI, EE = 61.6
2 = 30.8 hoooooooo.
To find the center of the CI, CCCCCCCCCCCC = (uuuuuuuuuu
bbbbbbbbbb+llllllllll bbbbbbbbbb)
2
. The center of this CI is
CCCCCCCCCCCC = uuuuuuuuuu bbbbbbbbbb+llllllllll bbbbbbbbbb
2 = 1990.8+1929.2
2 = 3920
2 = 1960 hoooooooo, which is the sample
mean. Remember every confidence interval for the population mean is
centered at the sample
mean.
(a) Now calculate confidence intervals for the mean expectancy of
all the new lightbulbs using
confidence levels of 90%, 92%, 94%, 98%, and 99%. Determine the
length, the margin of error
and center for each CI. I have filled in the information for the
97% confidence interval we
formed in the workbook.
Confidence level Confidence Interval Length of CI Margin of Error Center of CI
90%
92%
94%
97% 1929.2 to 1990.8 hours 61.6 hours 30.8
hours 1960 hours
98%
99%
(b) As the confidence level increases, what happens to the width of
the confidence interval? Use
clear, complete sentences to state and justify your answer.
(c) As the confidence level increases, what happens to the margin
of error? Use clear, complete
sentences to state and justify your answer.
(d) As the confidence level increases, what happens to the center
of the confidence interval? Use
clear, complete sentences to state and justify your
answer.
In: Statistics and Probability
2. Rossi et al. (2013) studied the relationship between cholesterol level and hypertension. They compared | ||
the total cholesterol measurements (mg/dl) for 15 patients with primary hypertension (PH) and another | ||
15 patients who were normotensive (NT). The results are given below. | ||
Patient Number | Primary hypertensive patients | Normotensive patients |
1 | 207 | 177 |
2 | 172 | 179 |
3 | 241 | 194 |
4 | 185 | 206 |
5 | 134 | 173 |
6 | 222 | 189 |
7 | 180 | 194 |
8 | 276 | 168 |
9 | 218 | 212 |
10 | 265 | 142 |
11 | 183 | 188 |
12 | 214 | 200 |
13 | 259 | 179 |
14 | 152 | 142 |
15 | 210 | 222 |
Can we conclude that PH patients have, on average, higher total cholesterol levels than NT patients? | ||
Make no assumptions and show all work out to the right. |
Ho: |
Ha: |
test-statistic: |
df: |
Exact P value for the test-statistic |
Conclusion relative to the hypothesis: |
What is the | ||
Statistical Power of this test?: | % |
In: Statistics and Probability
A bridal shop is slow with deliveries. If Karen orders her dress 6 months before her rehearsal dinner, there is a 75% chance that the dress will arrive on time for her rehearsal dinner. If Karen forgets to order her dress 6 months early, there is only a 20% chance that the dress will arrive on time for her rehearsal dinner. Because Karen is so busy planning her wedding, she estimates that there is only a 90% chance that she remembers to order her dress 6 months early.
a) What is the probability that the dress arrives on time for Karen's rehearsal dinner?
b) If the dress arrives on time, what is the probability that Karen forgot to order her dress 6 months early?
In: Statistics and Probability
Problem 6
The unemployment rate (UR) for PEI by quarter was as follows:
UR T (Time)
Year Quarter Rate For Regression
2018 Q1 12.0 1
Q2 7.1 2
Q3 8.2 3
Q4 10.2 4
2019 Q1 12.2 5
Q2 6.9 6
Q3 7.1 7
Q4 9.9 8
In: Statistics and Probability
The following is a summary of data for 960 branch managers in the two major regions of a Canadian Bank:
Education Level |
Domestic Region |
International Region |
TOTAL |
No Degree |
120 |
20 |
140 |
Bachelor’s Degree |
420 |
100 |
520 |
Post-graduate Degree |
250 |
50 |
300 |
TOTAL |
790 |
170 |
960 |
1. State the null and alternative hypotheses for a Chi Square test to determine if managers’ education level is dependent of which region they are from. (2 Points)
2. State the rejection rule using the critical value approach. Let alpha = 0.05. (2 Points)
3. Calculate the expected frequency for the cell “No Degree” and “International Region” (2 Points)
4. If the Chi Square statistic is 2.176, what is your conclusion? (2 Points)
In: Statistics and Probability
Wall Street traders are anxiously waiting for the federal government’s release of the August numbers for nonfarm payrolls. Last year month of August showed an average of 120,000 new jobs with a standard deviation of 20,000. A sample of 100 nonfarm payrolls taken earlier in the week shows a sample mean of 117,000. Financial analysts often call such a sample mean the “whisper number”. Conduct a hypothesis test to determine whether the whisper number justifies a conclusion of a statistically significant change in the number of new jobs with respect to last year. Allow for 5% error in the test. The hypothesis setting for the test follows. H0 : µ = 120,000 Ha : µ ≠ 120,000 a. (5pt) Conduct hypothesis test using a critical-value approach. b. (3pt) Conduct a hypothesis test using a p-value approach. c. (3pt) According to the statistical analysis you have performed above, do you think the whisper number does justify a conclusion of a statistically significant change in the number of new jobs? WHY?
In: Statistics and Probability
Clearwater National Bank wants to compare the account checking practices by the customers at two of its branch banks – Cherry Grove Branch and Beechmont Branch. A random sample of 28 and 22 checking accounts is selected from these branches respectively. The sample statistics are shown on the next slide
Cherry Grove Beechmont
n 28 22
x $1025 $910
s $150 $125
Let us develop a 99% confidence interval estimate of the difference between the population mean checking account balances at the two branch banks.
Please, show work.
In: Statistics and Probability
A manufacturer wants to compare the number of defects on the day shift with the number on the evening shift. A sample of production from recent shifts showed the following defects: Day Shift 5 8 7 6 9 7
Evening Shift 8 10 7 11 9 12 14 9
The objective is to determine whether the mean number of defects on the night shift is greater than the mean number on the day shift at the 95% confidence level.
State the null and alternate hypotheses.
What is the level of significance? What is the test statistic? What is the decision rule? Use the Excel Data Analysis pack to analyze the problem. Include the output with your answer. (Note: You may calculate by hand if you prefer). What is your conclusion? Explain. Does the decision change at the 99% confidence level?
In: Statistics and Probability
The cost of weddings in the United States has skyrocketed in recent years. As a result, many couples are opting to have their weddings in the Caribbean. A Caribbean vacation resort recently advertised in Bride Magazine that the cost of a Caribbean wedding was less than $10,000. Listed below is a total cost in $000 for a sample of 8 Caribbean weddings. At the .01 significance level is it reasonable to conclude the mean wedding cost is less than $10,000 as advertised? |
9.0 |
9.1 |
8.5 |
9.1 |
10.8 |
9.7 |
8.5 |
9.4 |
(a) |
State the null hypothesis and the alternate hypothesis. Use a .01 level of significance. (Enter your answers in thousands of dollars.) |
H0: μ ≥ | |
H1: μ < | |
(b) |
State the decision rule for .01 significance level. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) |
Reject H0 if t < |
(c) |
Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) |
Value of the test statistic |
(d) |
At the .01 significance level is it reasonable to conclude the mean wedding cost is less than $10,000 as advertised? |
(Click to select)RejectDo not reject H0. The cost is (Click to select)lessnot less than $10,000. |
In: Statistics and Probability
Problem 5
Research into the relationship between hours of study and grades shows widely different conclusions. A recent survey of graduates who wrote the Graduate Management Admissions Test (GMAT) had the following results.
Hours
Studied Average
(Midpoint) Score
40 200
50 290
65 335
75 445
85 530
105 650
95 690
In: Statistics and Probability
2. An environmentalist is interested in estimating the mean time
between eruptions of Old
Faithful Geyser in Yellowstone National Park. Over the course of a
year, she takes a random
sample of the time intervals (in minutes) between eruptions. Her
results are recorded in the
following table. Both the population mean and standard deviation
are unknown.
Time Between Eruptions (in minutes)
63 63 71 77 81 65
67 84 72 75 70 70
93 83 85 79 90 74
81 74 80 65 70 84
83 78 71 67 97 88
62 61 57 86 70 77
78 75 67 89 93 81
86 65 70 77 83 76
76 67 99 75 76 83
97 93 73 81 85 90
(a) Construct a stem-and-leaf diagrams of the times using two lines
per stem.
(b) Describe the stem-and-leaf diagram. When describing a graph,
you must describe the shape,
center and spread.
(c) Form a 95% confidence interval for the mean time between all
eruptions of Old Faithful
Geyser. Use clear, complete sentences to interpret the
interval.
Confidence Interval
(d) Based on the 95% confidence interval formed in part (c), is it
plausible that the mean time
between all eruptions of Old Faithfull geyser is 77 minutes? Why or
why not? Use clear,
complete sentences to state and justify your answer.
(e) Based on the 95% confidence interval formed in part (c), is it
plausible that the mean time
between all eruptions of Old Faithfull geyser is 90 minutes? Why or
why not? Use clear,
complete sentences to state and justify your answer.
In: Statistics and Probability
USE R software
Suppose that we want to test H0 : F = G, where F is the distribution of weight for the casein feed group and G is the distribution of weight for the sunflower feed group of the chickwts data. A test can be based on the two-sample Kolmogorov-Smirnov statistic
chickwts
weight feed
1 179 horsebean
2 160 horsebean
3 136 horsebean
4 227 horsebean
5 217 horsebean
6 168 horsebean
7 108 horsebean
8 124 horsebean
9 143 horsebean
10 140 horsebean
11 309 linseed
12 229 linseed
13 181 linseed
14 141 linseed
15 260 linseed
16 203 linseed
17 148 linseed
18 169 linseed
19 213 linseed
20 257 linseed
21 244 linseed
22 271 linseed
23 243 soybean
24 230 soybean
25 248 soybean
26 327 soybean
27 329 soybean
28 250 soybean
29 193 soybean
30 271 soybean
31 316 soybean
32 267 soybean
33 199 soybean
34 171 soybean
35 158 soybean
36 248 soybean
37 423 sunflower
38 340 sunflower
39 392 sunflower
40 339 sunflower
41 341 sunflower
42 226 sunflower
43 320 sunflower
44 295 sunflower
45 334 sunflower
46 322 sunflower
47 297 sunflower
48 318 sunflower
49 325 meatmeal
50 257 meatmeal
51 303 meatmeal
52 315 meatmeal
53 380 meatmeal
54 153 meatmeal
55 263 meatmeal
56 242 meatmeal
57 206 meatmeal
58 344 meatmeal
59 258 meatmeal
60 368 casein
61 390 casein
62 379 casein
63 260 casein
64 404 casein
65 318 casein
66 352 casein
67 359 casein
68 216 casein
69 222 casein
70 283 casein
71 332 casein
In: Statistics and Probability
Restate the question that the researcher is investigating?
What type of test is appropriate for this question?
Write out the model statements in words (make sure you include null model too)
What are the hypotheses (all of them)
Run the appropriate statistical test in Minitab (for this example you do not need to check for normality, variance, outliers etc, just run the test). Paste the output here. Paste it so it is easy to read.
Run a post-hoc test if appropriate. Paste results here as appropriate.
Summarize what the results are telling you. What is the take home message that you want to tell your audience. (I am not requiring a final graph for this assignment)
Salary course Subject
1700 Humanities
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2800 Humanities
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In: Statistics and Probability