Historically, the number of cars arriving per hour at Lundberg’s Car
Wash is observed to be the following:
Number of Cars Arriving | Frequency |
---|---|
4 | 10 |
5 | 30 |
6 | 50 |
7 | 65 |
8 | 45 |
Total: | 200 |
a. Set up a probability distribution table (including the lower end of
the probability range) for the car arrivals.
b. Simulate 25 hours of car arrivals. What is the average number of
arrivals per hour?
c. Repeat part b multiple times (by pressing F9). Over what range
does the average number of arrivals vary?
d. Now simulate 500 hours of car arrivals. What is the average
number of arrivals per hour?
e. Repeat part d multiple times (by pressing F9) Over what range
does the average number of arrivals vary?
f. Do your answers for part c and e differ? Why or why not?
In: Statistics and Probability
Use the sample data and confidence level given below to complete parts (a) through (d).
In a study of cell phone use and brain hemispheric dominance, an Internet survey was e-mailed to 2510 subjects randomly selected from an online group involved with ears. 1092 surveys were returned. Construct a 95% confidence interval for the proportion of returned surveys.
a) Find the best point estimate of the population proportion p.
___ (Round to three decimal places as needed.)
b) Identify the value of the margin of error E.
___ (Round to three decimal places as needed.)
c) Construct the confidence interval.
___ < p < ___ (Round to three decimal places as needed.)
d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
A. There is a 95% chance that the true value of the population proportion will fall between the lower bound and the upper bound.
B. 95% of sample proportions will fall between the lower bound and the upper bound.
C. One has 95% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.
D. One has 95% confidence that the sample proportion is equal to the population proportion.
In: Statistics and Probability
The following table summarizes the results from a two-factor study with 3
levels of Factor A and 4 levels of Factor B using a separate sample of 5
participants in each treatment condition. Fill in the missing values. Make
sure to show your work.
Source
SS
df
MS
F
Between
treatments
650
Factor A
5
0
Factor B
AxB
interaction
120
Within treatments
2
5
Total
In: Statistics and Probability
Explain the difference between continuous random variables and discrete random variables. please give examples!
In: Statistics and Probability
A manufacturer wants to compare the number of defects on the day shift with the number on the evening shift. A sample of production from recent shifts showed the following defects:
Day Shift 5 8 7 6 9 7
Evening Shift 8 10 7 11 9 12 14 9
The objective is to determine whether the mean number of defects on the night shift is greater than the mean number on the day shift at the 95% confidence level.
In: Statistics and Probability
Why do we naturally tend to trust some strangers more than others? One group of researchers decided to study the relationship between eye color and trustworthiness. In their experiment the researchers took photographs of 80 students (20 males with brown eyes, 20 males with blue eyes, 20 females with brown eyes, and 20 females with blue eyes), each seated in front of a white background looking directly at the camera with a neutral expression. These photos were cropped so the eyes were horizontal and at the same height in the photo and so the neckline was visible. They then recruited 105 participants to judge the trustworthiness of each student photo. This was done using a 10-point scale, where 1 meant very untrustworthy and 10 very trustworthy. The 80 scores from each participant were then converted to z-scores, and the average z-score of each photo (across all 105 participants) was used for the analysis. Here is a summary of the results.
Eye color n x s
Brown 40 0.55 1.68
Blue 40 −0.37 1.54
Can we conclude from these data that brown-eyed students appear more trustworthy compared to their blue-eyed counterparts? Test the hypothesis that the average scores for the two groups are the same.
State the null and alternative hypotheses.
H0: μBrown = μBlue Ha: μBrown > μBlue
H0: μBrown = μBlue Ha: μBrown < μBlue
H0: μBrown ≠ μBlue Ha: μBrown > μBlue
H0: μBrown = μBlue Ha: μBrown ≠ μBlue
H0: μBrown ≠ μBlue
Ha: μBrown < μBlue
Report the test statistic, the degrees of freedom, and the P-value. (Round your test statistic to three decimal places, your degrees of freedom to the nearest whole number, and your P-value to four decimal places.)
t =
df =
P-value =
State your conclusion. (Use α = 0.05.)
We reject H0 and conclude that brown-eyed people seem more trustworthy according to this experiment.
We do not reject H0 and can not conclude that brown-eyed people seem more trustworthy according to this experiment.
In: Statistics and Probability
Testing ONE mean versus a claim (z or t)
Testing TWO means head to head (t)
1. What if we want to test MORE than TWO means?
2. What are the null hypotheses for each?
3. How do the null hypotheses change for ANOVA?
In: Statistics and Probability
In 2001 Kenkel and Terza published an article in which they investigated the impact on an individual's alcohol consumption of a physician's advice to reduce drinking. The simplified model below was estimated with their data set (although the econometric techniques used in the article are more complex than those we have discussed in this class).
DRINKS= 13.00 + 11.36 Advice-.20 EDUC+ 2.85 DIVSEP+14.20 UNEMP
(5.37) (-.65) (1.11) (2.75)
N = 500, R2 = 0.377, t-Statistics in parentheses
DRINKS = drinks consumed by the individual in the last two weeks
ADVICE = 1 if a physician had advised the individual to cut back on drinking alcohol, 0 otherwise
EDUC = years of schooling of the individual
DIVSEP = 1 if the individual is divorced or separated, 0 otherwise
UNEMP = 1 if the individual is unemployed, 0 otherwise
14. Which of the following best reflects the interpretation of the coefficient of determination, R2?
a. 37.7 percent of the variation in DRINKS is due to random (unexplained) variations.
b. 37.7 percent of the variation in DRINKS is explained by variation in the independent variables.
c. 37.7 percent of people listen to the advice of a physician in regards to their drinking behaviors.
d. 37.7 percent of the people in this sample drink.
15. Which of the following best reflects the interpretation of the coefficient on the variable EDUC?
a. For every additional year of schooling, the number of DRINKS decreases 0.2, ceteris paribus.
b. People with more education drink 20% less than those with less education, ceteris paribus.
c. For every additional year of schooling, people drink 20 percent less, ceteris paribus.
d. Consuming one additional DRINK (every 2 weeks) results in people completing .2 years less education, ceteris paribus.
16. Which of the following best reflects the interpretation of the coefficient on the variable UNEMP?
a. 14.20 percent of the people in this sample were unemployed, while 2.75 percent were heavy drinkers, ceteris paribus.
b. Consuming one additional DRINK (every 2 weeks) results in people being 14.20 percent more likely to be unemployed, ceteris paribus.
c. An unemployed person, on average, consumed 14.20 percent more drinks (in the last 2 weeks) than an employed person, ceteris paribus.
d. An unemployed person, on average, consumed 14.20 more drinks (in the last 2 weeks) than an employed person, ceteris paribus.
17. Conduct two-tailed hypothesis tests on the significance of each of the regression coefficients. Use the 5% level of significance and 120 degrees of freedom. What is the t-Critical value for these tests?
a. 3.374
b. 1.658
c. 1.980
d. 2.398
18. Conduct two-tailed hypothesis tests on the significance of each of the regression coefficients. Use the 5% level of significance and 120 degrees of freedom. Which coefficients are significantly different from 0?
a. The coefficients on EDUC and DIVSEP only
b. None of the coefficients are significant at the 5% level.
c. All four coefficients are significant at the 5% level.
d. The coefficients on ADVICE and UNEMP only
In: Statistics and Probability
Salaries of 39 college graduates who took a statistics course in college have a mean, x overbar, of $ 68 comma 900. Assuming a standard deviation, sigma, of $19 comma 972, construct a 99% confidence interval for estimating the population mean mu.
In: Statistics and Probability
An amusement park studied methods for decreasing the waiting time (minutes) for rides by loading and unloading riders more efficiently. Two alternative loading/unloading methods have been proposed. To account for potential differences due to the type of ride and the possible interaction between the method of loading and unloading and the type of ride, a factorial experiment was designed. Use the following data to test for any significant effect due to the loading and unloading method, the type of ride, and interaction. Use . Factor A is method of loading and unloading; Factor B is the type of ride.
Type of Ride |
|||
Roller Coaster | Screaming Demon | Long Flume | |
Method 1 | 41 | 50 | 53 |
43 | 42 | 49 | |
Method 2 | 48 | 51 | 50 |
50 | 47 | 46 |
Set up the ANOVA table (to whole number, but p-value to 2 decimals and F value to 1 decimal, if necessary).
Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F | p-value |
Factor A | |||||
Factor B | |||||
Interaction | |||||
Error | N/A | ||||
Total |
In: Statistics and Probability
The following table compares the completion percentage and interception percentage of 5 NFL quarterbacks. Completion Percentage 57 59 61 65 65 Interception Percentage 4.8 4.7 4.5 3.1 1.1 Table
Step 4 of 5 : Construct the 98% confidence interval for the slope. Round your answers to three decimal places.
In: Statistics and Probability
The Diabetes Control and Complications Trial followed diabetes patients diagnosed with retinopathy before joining the study. They were randomly assigned to one of two treatments and monitored for 6 years. The study found that 121 of the 344 patients assigned to the conventional treatment showed a sustained progression of their original retinopathy. In contrast, only 62 of the 376 patients assigned to the intensive treatment had sustained retinopathy progression.
Find a point estimate of the difference between the proportion of conventional treatment patients with sustained retinopathy progression and the proportion of intensive treatment patients with sustained retinopathy progression. (Use 3 decimal places)
In: Statistics and Probability
X and Y are the future lifetimes of two machines. The joint PDF of the two random variables is f(x, y) = 12(x+y+1)^-5, x>), y>0. Calculate E(X|Y = 2).
In: Statistics and Probability
2) Male company employees aged 21 to 26 are found to drive an average of 19484 km a year. The annual mileage is normally distributed with a standard deviation of 6812 km. The company has decided to levy a user fee on those employees who are in the top 30%. Find the yearly mileage total of those who will be charged a user fee.
3) If α = 0.06, standard deviation is s = 3.15, sample mean is x= 12.7, and n = 500, find the confidence interval for the population mean.
In: Statistics and Probability
In: Statistics and Probability