In: Chemistry
A. BaCl2(aq)+K2SO4(aq)=
B. Pb(NO3)2(aq)+NaBr(aq)=
C.Fe(NO3)3(aq)+KCl(aq)=
(A) K2SO4 (aq) + BaCl2 (aq) → 2 KCl (aq) + BaSO4 (s)
Ionic: Ba+2(aq) + 2Cl-(aq) + 2K+(aq) + SO4-2(aq)-->BaSO4(s) + 2K+(aq) + 2Cl-(aq)
Net ionic :Ba+2(aq) + SO4-2(aq)-->BaSO4(s)
(B) Pb(NO3)2 + 2NaBr → PbBr2 + 2NaNO3
ionic : Pb2+(aq) + 2NO3-(aq) + 2Na+ (aq) + 2Br− (aq) → PbBr2(s)↓ + 2Na+(aq) + 2NO3-(aq)
net ionic Pb2+ (aq) + 2Br− (aq) → PbBr2(s)↓
(C) Fe(NO3)3 + 3KCl = FeCl3 + 3KNO3
Practice it by yourself !! (break each ion)
For writing solubility product , consider this reaction aA(s) ⇌ cC (aq) + dD (aq)
only aqueous products are written , solid are ignored
Ksp = [C]c[D]d
For (A) Ksp= 1 / [Ba2+][SO42-]
Similarly do for rest !!