Question

1) Dynamic Allocation (c++)

a. Create two integer variables x and y, initialize them with different values.

b. Use dynamic memory allocation, declare px and py as address of x and y separately.

c. Print out x, y, px, py, &x, &y, *px, *py.  

d. Let py = px, and *py = 100

e. Print out x, y, px, py, &x, &y, *px, *py.

g. Print out *px++, x, px

Answer 1

#include<iostream>
using namespace std;
int main(){
        int x=10,y=20;
        int *px=new int;
        int *py=new int;
        px=&x;
        py=&y;
        cout<<x<<" "<<y<<" "<<*px<<" "<<*py<<endl;
        py=px;
        *py=100;
        cout<<x<<" "<<y<<" "<<py<<" "<<&x<<" "<<&y<<" "<<*px<<" "<<*py<<endl;
        cout<<*px++<<" "<<x<<" "<<px<<endl;
}

NOTE : PLEASE COMMENT BELOW IF YOU HAVE CONCERNS.

I AM HERE TO HELP YOUIF YOU LIKE MY ANSWER PLEASE RATE AND HELP ME IT IS VERY IMP FOR ME