Question

In: Chemistry

What is the pH of a 0.1M solution of monosodium succinate pk1= 4.19 pk2= 5.56

What is the pH of a 0.1M solution of monosodium succinate
pk1= 4.19
pk2= 5.56

Solutions

Expert Solution

Monosodium succinate = C4H5NaO4

    C4H5NaO4 -----------------------C4H5O4- + Na+

               C4H5O4-     H2O ----------------- C4H5O4H + OH-

                  0.1                                              0                  0

                   -x                                               +x               +x

                 0.1-x                                          +x                   +x

Ka = [C4H5OH][OH-]/[C4H5O4-]

Pka1 = 4.19

-log(Ka1) = 4.19

Ka1 = 10^-4.19

Ka1= 6.46x10^-5

6.46x10^-5 = x*x/(0.1-x)

for solving the equation

x= 0.0025

[OH-] =0..0025M

-log[OH-] = -log(0.0025)

POH= 2.60

PH+POH=14

PH= 14 - POH

PH = 14- 2.60

PH = 11.4

queen_honey_blossom answered 1 year ago
Next > < Previous

Related Solutions

PK1 and PK2 are protein kinases involved in a phosphorylation cascade. If either protein is inactive...
PK1 and PK2 are protein kinases involved in a phosphorylation cascade. If either protein is inactive due to a mutation the response is not observed. A different mutation causes PK1 to be permanently active. This activity induces a response even if PK2 is inactive. Which of the following conclusions is supported by the above information? A. PK1 activates PK2 B. PK2 activates PK1 C. PK2 is a transcription factor D. PK1 inhibits PK2 Ca2+ can act as a second messenger...
what is the ph of a 0.1M hydrochloric acid solution? A 1.0×10^-3M HCl solution? A 1.0...
what is the ph of a 0.1M hydrochloric acid solution? A 1.0×10^-3M HCl solution? A 1.0 × 10^-8 M HCl solution?
You measured the pH of a 0.1M HCl solution. If you had diluted this solution by...
You measured the pH of a 0.1M HCl solution. If you had diluted this solution by adding 100mL of water, what happens to the concentration of H3O+?
The tetrapeptide, NRMD, exhibits four pKa values: pK1 = 1.88, pK2 = 3.65, pK3 = 8.80,...
The tetrapeptide, NRMD, exhibits four pKa values: pK1 = 1.88, pK2 = 3.65, pK3 = 8.80, and pK4 = 12.48. What is the isoelectric point for this peptide? Group of answer choices pI = 2.8 pI = 5.3 pI = 6.2 pI = 8.1 pI = 10.6
Consider the titration of 50.0ml of 0.0200M diprotic acid with pk1=4.00 and pk2=8.00 by 0.100M NaOH....
Consider the titration of 50.0ml of 0.0200M diprotic acid with pk1=4.00 and pk2=8.00 by 0.100M NaOH. Calculate the pH at the following points: 0ml, 2ml, 5ml, 7ml, 10ml, 15ml, 20ml, 25ml
Order these chemical species by increasing pH of an 0.1M aqueous solution of each. That is,...
Order these chemical species by increasing pH of an 0.1M aqueous solution of each. That is, imagine making an 0.1M solution of each species. Select 1 next to the species that makes the solution with the lowest pH. Select 2 next to the species that makes the solution with the next higher pH, and so on. Notice that some of the rankings have been filled in for you already. Also notice that water is on the list. For that particular...
Order these chemical species by increasing pH of an 0.1M aqueous solution of each. That is,...
Order these chemical species by increasing pH of an 0.1M aqueous solution of each. That is, imagine making an 0.1M solution of each species. Select 1 next to the species that makes the solution with the lowest pH. Select 2 next to the species that makes the solution with the next higher pH, and so on. Notice that some of the rankings have been filled in for you already. Also notice that water is on the list. For that particular...
125.0-mL aliquot of 0.124 M diprotic acid H2A (pK1 = 4.03, pK2 = 8.06) was titrated...
125.0-mL aliquot of 0.124 M diprotic acid H2A (pK1 = 4.03, pK2 = 8.06) was titrated with 1.24 M NaOH. Find the pH at the following volumes of base added: Vb = 0.00, 1.80, 6.25, 11.50, 12.50, 13.50, 18.75, 24.00, 25.00, and 28.00 mL. (Assume Kw = 1.01 ✕ 10−14.)
The pH of 0.1M NaCl is 7.14. After 1 drop of 0.1M HCl the pH change...
The pH of 0.1M NaCl is 7.14. After 1 drop of 0.1M HCl the pH change to 3.59. And after another 1 drop of 0.1M HCl the pH become 3.13. Why does pH change significantly 7.14 to 3.59? And also why the pH doesn't change very much after another 1 drop of 0.1M HCl (3.59 to 3.13)?
For the triprotic acid, H+glutamic acid, pK1=2.23, pK2=4.42 and pK3=9.95. If one has 0.10L of a...
For the triprotic acid, H+glutamic acid, pK1=2.23, pK2=4.42 and pK3=9.95. If one has 0.10L of a 1.0E-2 M solution and titrates it with 0.255 L of a 1.0E-2 M KOH solution, what is the pH of the resulting solution? The answer is 10.04. I just have no clue how to get there.
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT