Question

Driving Force is a golf ball manufacturer.

Their R & D department have been developing a type of golf ball with a new dimpling pattern that is designed to increase the flight distance of the ball. They are at the testing stage and run an experiment to test the mean flight distance for the new type of ball compared to a standard one. A special device is used to fire the balls at a set force and angle. A sample of 30 of the new balls (sample A) and 30 standard balls (sample B) are fired using the device and the distance travelled (in feet) is recorded for each ball.

Download the data:

Sample A 807 784 808 770 758 790 768 787 769 799 742 747 754 789 801 765 767 742 783 821 722 810 795 722 804 726 779 810 732 819

Sample B 808 787 800 775 772 778 704 782 805 809 844 693 810 794 850 748 721 786 718 731 796 777 709 675 788 764 796 785 725 761

Conduct an appropriate one-tailed hypothesis test. Assume that the population variances are not equal.

a)From the following options, select the correct null and alternate hypotheses for this test: A:H0: μA = μ B, Ha: μA < μB B:H0: μA = μB, Ha: μA ≠ μB C:H0: μA < μB, Ha: μA > μB D:H0: μA = μB, Ha: μA > μB

The correct null and alternate hypotheses for this test are: ? (a, b ,c or d)

b)Calculate the test statistic. Give your answer to 3 decimal places. t = ?

c)At a significance level of 0.05, the null hypothesis is .? (reject or not rejected)

That is, you can state that there is ? (proof, significant evidance, not significant evidence) to conclude that the ? (population mean flight distance or sample mean flight distance) of the new type of golf ball is ? (less than, equal to, greater than) that of the standard golf ball.

Answer 1

----------------------------------------------------------------------------------------------------------------------