In: Statistics and Probability
A realtor in Florida claims that more than 75% of retired couples prefer apartment living to single-unit housing. A random sample of 100 couples shows that 81 prefer apartment living. Test the claim of the realtor at the 5% level of significance. (Hint: The realtor's claim, that more than 75% prefer apartment living, corresponds to the alternative hypothesis. The null will state that 75% prefer apartment living)
Solution :
This is the right tailed test .
The null and alternative hypothesis is
H0 : p = 0.75
Ha : p > 0.75
= x / n = 81 / 100 = 0.81
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
= 0.81 - 0.75 / [(0.75 * 0.25) / 100]
= 1.386
P-value = 0.0829
= 0.05
P-value >
Fail to reject the null hypothesis .
There is sufficient evidence to suggest that the realtor in Florida claims that more than 75% of retired couples prefer apartment living to single-unit housing