Question

Consider the reaction between mercury (II) nitrate and sodium bromide. Write the BALANCED MOLECULAR, COMPLETE and NET IONIC EQUATIONS to show the formation of the solid.

Molecular: _________________________________________________________

Complete Ionic:________________________________________________________

Net Ionic:_________________________________________________________________

Answer 1

Mercury (II) Nitrate = Hg(NO_{​​​​​3}​)₂

Sodium Bromide = NaBr

Hg(NO_{​​​​​3})_{2 (aq)} + NaBr_(aq) ----> HgBr_{2 (s)} + NaNO_{3 (aq)}

a. Molecular Balanced equation is: Hg(NO_{​​​​​3})₂ + 2NaBr ----> HgBr_​​​2 + 2NaNO₃

b. Hg(NO_{​​​​​3})_{2 (aq)} = Hg​​​​2+ _(aq)  + 2NO₃^- _(aq)

2NaBr _(aq) = 2Na⁺_(aq) + 2Br^​​-_(aq)

HgBr_​​​2 will not decompose

2NaNO_{3 (aq)} = 2Na⁺ _(aq) + 2NO_{​​​​​3}^{​​​​-} _(aq)

Complete ionic Equation is: Hg​​​​2+ _(aq)  + 2NO₃^- _(aq) + 2Na⁺_(aq) + 2Br^​​-_(aq) ----> HgBr_{​​​2 (s)} +  2Na⁺ _(aq) + 2NO_{​​​​​3}^{​​​​-} _(aq)

Cancel 2NO₃^- _(aq) and 2Na+ from both side. We get,

Net ionic Equation is: Hg​​​​2+ _(aq)+ 2Br^​​-_(aq) ----> HgBr_{​​​2 (s)}