Question

An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow.

		Analyzer
		Computerized	Electronic
Car	Compact	52	43
	Intermediate	55	43
	Full-sized	61	46

Use α = 0.05 to test for any significant differences.

State the null and alternative hypotheses.

H₀: μ_Compact = μ_Intermediate = μ_Full-sized
H_a: μ_Compact ≠ μ_Intermediate ≠ μ_Full-sizedH₀: μ_Computerized ≠ μ_Electronic
H_a: μ_Computerized = μ_Electronic    H₀: μ_Computerized = μ_Electronic
H_a: μ_Computerized ≠ μ_ElectronicH₀: μ_Compact ≠ μ_Intermediate ≠ μ_Full-sized
H_a: μ_Compact = μ_Intermediate = μ_Full-sizedH₀: μ_Computerized = μ_Electronic = μ_Compact = μ_Intermediate = μ_Full-sized
H_a: Not all the population means are equal.

Find the value of the test statistic. (Round your answer to two decimal places.)

2

Find the p-value. (Round your answer to three decimal places.)

p-value = 3

State your conclusion.

Reject H₀. There is not sufficient evidence to conclude that the mean tune-up times are not the same for both analyzers.Do not reject H₀. There is not sufficient evidence to conclude that the mean tune-up times are not the same for both analyzers.    Do not reject H₀. There is sufficient evidence to conclude that the mean tune-up times are not the same for both analyzers.Reject H₀. There is sufficient evidence to conclude that the mean tune-up times are not the same for both analyzers.

can someone explain how to get the p value using a ti-83/84

Answer 1

Randomized blocks ANOVA
	Mean	n	Std. Dev
	56.000	3	4.583	Computerized
	44.000	3	1.732	Electronic
	47.500	2	6.364	Compact
	49.000	2	8.485	Intermediate
	53.500	2	10.607	Full sized
	50.000	6	7.266	Total
ANOVA table
Source	SS	df	MS	F	p-value
Treatments	216.00	1	216.000	48.00	.0202
Blocks	39.00	2	19.500	4.33	.1875
Error	9.00	2	4.500
Total	264.00	5

Hypothesis:

Ho: computerized = electronics

Ha: computerized electronics

Find the value of the test statistic. (Round your answer to two decimal places.)

Test Statistic=48

Find the p-value. (Round your answer to three decimal places.)

p-value = 0.020

State your conclusion.

Reject H₀. There is sufficient evidence to conclude that the mean tune-up times are not the same for both analyzers.