Question

Last year, 35.7 % of all employees at a large company enrolled in at least one wellness class at the company's site. A survey is sent out to a sample employees at the start of the new fiscal year to see if a greater percentage is planning to take a wellness class this year. Survey responses are received from 162 employees and 76 indicate that they plan to enroll in a wellness class. Test the appropriate hypotheses using a significance level of 0.10.

• H0:H0: Select an answer p p̂  ? < = > ≠     Ha:Ha: Select an answer p p̂  ? < ≠ >  
• αα =    decision rule: Reject H0H0 if probability ? < > ≠  αα  
• Test Statistic: z =   (Note: round the z-score to two decimal places - carry at least four decimal places throughout all of your calculations)
• probability =   (Note: round the probability to four decimal places)
• decision: Select an answer Reject H₀ Fail to reject H₀
• Conclusion: At the 0.10 level, there Select an answer is not is  significant evidence to conclude the percentage of employees that plan to enroll in at least one wellness class in the upcoming year is Select an answer less than greater than different than  than 35.7%.

Answer 1

given data and some necessary calculation are:-

sample size (n) = 162

here, we will do 1 proportion Z test.

hypothesis:-

rejection rule:-

reject the null hypothesis,

p value < 0.10 (level of significance)

test statistic be:-

p value :-

[from standard normal table]

decision:-

p value = 0.0014 < 0.10

we reject the null hypothesis.

conclusion:-

At the 0.10 level, there is significant evidence to conclude, the percentage of employees that plan to enroll in at least one wellness class in the upcoming year is greater than 35.7%.

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