Question

In: Statistics and Probability

In six packages of "The Flintstones® Real Fruit Snacks" there were five Bam-Bam snack pieces. The...

In six packages of "The Flintstones® Real Fruit Snacks" there were five Bam-Bam snack pieces. The total number of snack pieces in the six bags was 61. We wish to calculate a 96% confidence interval for the population proportion of Bam-Bam snack pieces.

  • Part (a)

    Define the random variables X and P' in words.

    X is the proportion of Bam-Bam snacks in a sample of 61 snack pieces. P' is the proportion of Bam-Bam pieces in a bag of snacks.X is the proportion of Bam-Bam snacks in a bag of snacks. P' is the proportion of Bam-Bam pieces in a sample of 61 snack pieces.     X is the number of Bam-Bam snacks in a sample of 61 snack pieces. P' is the proportion of Bam-Bam pieces in a bag of snacks.X is the number of Bam-Bam snacks in a bag of snacks. P' is the number of Bam-Bam pieces in a sample of 61 snack pieces.

  • Part (b)

    Which distribution should you use for this problem? (Enter your answer in the form z or tdf where df is the degrees of freedom.)

    Explain your choice.The Student's t-distribution should be used because
    npq
    ≤ 10, which implies a small sample.The binomial distribution should be used because the two outcomes are "Bam-Bam" and "Not Bam-Bam".     The standard normal distribution should be used because we are interested in proportions.The Student's t-distribution should be used because we do not know the standard deviation.
  • Part (c)

    Calculate p'. (Round your answer to three decimal places.)

    p' =

  • Part (d)

    Construct a 96% confidence interval for the population proportion of Bam-Bam snack pieces per bag. (Round your answers to three decimal places.)(i) State the confidence interval.
      ,  


    (ii) Sketch the graph.

    CL =

    α
    2
    =
    α
    2
    =


    (iii) Calculate the error bound.
  • Part (e)

Solutions

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