Find the critical value z Subscript c necessary to form a confidence interval at the level...

Find the critical value z Subscript c necessary to form a confidence interval at the level of confidence shown below. zc= 0.87

Solutions

Expert Solution

Answer:

Given Data

The level of significance is obtained below :

Here , confidence level is 0.87 ,

The level of significance is 0.935

Explanation

The level of significance is obtained by dividing the c with 2 , and subtracting from 1.

The critical value for 0.87 level of confidence is obtained below :

The value is obtained below:

That is ,

Procedure for finding the z - value is listed below :

From the table of standard normal distribution ,locate the probability value of 0.935.
Move left until the first column is reached . Note the value as 1.5.
Move upward until the top row is reached . Note the value as 0.01.
The intersection of the row and column values gives the area to the two tail of z.

That is ,

The critical value for 0.87 level of confidence is 1.51

Explanation

Locate the probability of 0.935 in the standard normal table and identify the corresponding row and column values to obtain the critical value for 0.87 level of confidence .

The critical value for 0.87 level of confidence is 1.51.

****Please like it...

It is important to me...

Thank you for supporting me.....

orchestra answered 1 year ago

Next > < Previous

Related Solutions

Find the critical value zc that is necessary to form a confidence interval at the level...

Find the critical value zc that is necessary to form a confidence interval at the level of confidence shown below. c=0.81 zc=

A) Find the z critical value for a 90% confidence level: Zc= B) Find the z...

A) Find the z critical value for a 90% confidence level: Zc= B) Find the z critical value for an 84% confidence level: Zc= C) The higher the confidence, the narrower the confidence interval True or False D) The greater the sample size, the mnarrower the confidence interval True or False E) In a recent study of 84 eighth graders, the mean number of hours per week that they watched TV was 22.3. Assume population standard deviation is 5.8 hours....

Find the critical z value for a confidence level of 94%. Critical Value= round answer to...

Find the critical z value for a confidence level of 94%. Critical Value= round answer to 2 decimal places) Out of 300 people sampled, 246 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places I am 99% confident that the proportion of people who have kids is between and Out of 300 people sampled, 255 had kids. Based on this, construct a 95%...

1. Find the critical value ?) ??/z 2 , for a 96% confidence level. ?) ??/z...

1. Find the critical value ?) ??/z 2 , for a 96% confidence level. ?) ??/z 2 , for a 99.5% confidence level. ?) ??/z 2 , for a 98% confidence level and for a sample of size 24. ?) ta/z 2 , for a 90% confidence level and for a sample of size 39.

find the critical value Z α/2 when the confidence level is 92%.

Find the critical value t/α2 needed to construct a confidence interval of the given level with...

Find the critical value t/α2 needed to construct a confidence interval of the given level with the given sample size. Round the answers to three decimal places. (a) For level 99% and sample size 9 (b) For level 99.5% and sample size 14 (c) For level 80% and sample size 29 (d) For level 90% and sample size 11

Fill in the blank. A critical? value, z Subscript alpha z??, denotes the? _______. A critical?...

Fill in the blank. A critical? value, z Subscript alpha z??, denotes the? _______. A critical? value, z Subscript alpha z??, denotes the ?

1) For a confidence level of 92%, find the Z-critical value 2) If n = 500...

1) For a confidence level of 92%, find the Z-critical value 2) If n = 500 and ˆpp^ (p-hat) = 0.7, construct a 99% confidence interval. 3) Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 405 drivers and find that 299 claim to always buckle up. Construct a 80% confidence interval for the population proportion that claim to always buckle up. 4) A political candidate...

Confidence interval when sigma is unknown. 2. Find the critical value tα2 for the given level...

Confidence interval when sigma is unknown. 2. Find the critical value tα2 for the given level and sample size: Level 90%, Sample size is 13, df = , so the critical value is: = Level 98%, Sample size is 10 df = , so the critical value is: = Level 80%, Sample size is 17 df = , so the critical value is: = Level 99%, Sample size is 77 df = ,...

Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided...

Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided by 2, (b) find the critical value t Subscript alpha divided by 2, (c) state that neither the normal nor the t distribution applies. Confidence level 98%; n=23 SD= 26.2; population appears to be normally distributed.

Subjects