Question

The average weight of a line of oranges is 16 g. Average juice content of the fruit is 28 ml. farmers one to select for smaller oranges with a higher juice content. You know that narrow sense heritability for size is 0.80 and for juice content is 0.60. A tree producing oranges with an average weight of 12 g in juice content of 30 A tree producing oranges with an average weight of 12 g in juice content of 30ml is self-fertilized to produce a line of smaller, juicy oranges. What trait is most responsive to selection: size, juice, they are equal

Answer 1

ANSWER :-

For the average weight of the oranges, the selection differential is calculated as :-

S = mean of parents selected - mean of the orange plant population

= 12 g - 16 g

= (-4) g

R (Response to selection) = h²S

= (0.80) (-4)

= (-3.20)

For the average juice content of the oranges, the selection differential is calculated as :-

S = mean of the parents selected - mean of the orange plant population

= 30 ml - 28 ml

= 2

R (Response to selection) = h²S

= (0.60) (2)

= (1.20)

Taking into consideration, there are two different values with the value for size of oranges indicates (16 g - 3.2 g = 12.8 g) or a decrease in the size of the oranges as compared to the value of (28 ml + 1.20 ml = 29.20 ml) for the juice content of the oranges. The value for juice content is intermediate for that between the selected parents and population (line) whereas there is a significant decrease in the size of the oranges which may be due to response to selection indicating that size shows maximum response to selection.