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In: Statistics and Probability

A machine that is programmed to package 1.20 pounds of cereal in each cereal box is...

A machine that is programmed to package 1.20 pounds of cereal in each cereal box is being tested for its accuracy. In a sample of 42 cereal boxes, the mean and the standard deviation are calculated as 1.26 pounds and 0.15 pound, respectively. (You may find it useful to reference the appropriate table: z table or t table) a. Select the null and the alternative hypotheses to determine if the machine is working improperly, that is, it is either underfilling or overfilling the cereal boxes. H0: µ ≥ 1.20; HA: µ < 1.20 H0: µ ≤ 1.20; HA: µ > 1.20 H0: µ = 1.20; HA: µ ≠ 1.20 b-1. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) b-2. Find the p-value. p-value < 0.01 p-value 0.10 0.05 p-value < 0.10 0.01 p-value < 0.02 0.02 p-value < 0.05 c-1. What is the conclusion at the 1% significance level? Reject H0 since the p-value is greater than significance level. Reject H0 since the p-value is smaller than significance level. Do not reject H0 since the p-value is greater than significance level. Do not reject H0 since the p-value is smaller than significance level. c-2. Can you conclude that the machine is working improperly? Yes No

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