In: Statistics and Probability
The following table shows the grain yield of rice at six seeding rates (Mg/ha). This was replicated 4 times. The primary objective is to discover if there is a significant difference among the seeding rates.
|
Seeding rate (kg/ha) |
||||||
|
Rep |
25 |
50 |
75 |
100 |
125 |
150 |
|
1 |
5.1 |
5.3 |
5.3 |
5.2 |
4.8 |
5.3 |
|
2 |
5.4 |
6 |
5.7 |
4.8 |
4.8 |
4.5 |
|
3 |
5.3 |
4.7 |
5.5 |
5 |
4.4 |
4.9 |
|
4 |
4.7 |
4.3 |
4.7 |
4.4 |
4.7 |
4.1 |
Run a INITIAL appropriate test at alpha = 0.05
H0: There is no significant difference among the seeding rates.
H1: There is a significant difference among the seeding rates.
Let the los be alpha = 0.05
From the given data, Given n = 4 and k = 6
| Repeatation | |||||||
| 1 | 2 | 3 | 4 | Ti. | SS | Ti.^2/n | |
| 25 | 5.1 | 5.4 | 5.3 | 4.7 | 20.5 | 0.2875 | 105.0625 |
| 50 | 5.3 | 6 | 4.7 | 4.3 | 20.3 | 1.6475 | 103.0225 |
| 75 | 5.3 | 5.7 | 5.5 | 4.7 | 21.2 | 0.56 | 112.36 |
| 100 | 5.2 | 4.8 | 5 | 4.4 | 19.4 | 0.35 | 94.09 |
| 125 | 4.8 | 4.8 | 4.4 | 4.7 | 18.7 | 0.1075 | 87.4225 |
| 150 | 5.3 | 4.5 | 4.9 | 4.1 | 18.8 | 0.8 | 88.36 |
| Total Pj | 31 | 31.2 | 29.8 | 26.9 | 118.9 | 3.7525 | 590.3175 |
| Pj^2 /k | 160.1667 | 162.24 | 148.0067 | 120.6017 | 591.015 | ||

| Anova Table | |||||
| Source | df | SS | MSS | Var. Ratio | F-critic |
| B/w groups | 5 | 1.2671 | 0.2534 | 2.1261 | 2.9013 |
| Within Group | 18 | 3.7525 | |||
| i) B/w Subject | 3 | 1.9646 | |||
| ii) Error | 15 | 1.7879 | 0.1192 | ||
| Total: | 23 | 5.0196 |
Since F - value 2.1261 < F critical value 2.9013, so we accept H0
Thus we conclude that there is no significant difference among the seeding rates.