In: Statistics and Probability
An unknown metal has been found and the following experimental
results have been tabulated in the table below. The table contains
the grams of the unknown metal and the volume in milliliters of
water displacement. Find a linear model that express
mass as a function of the
volume.
Round your answers to 3 decimal places
grams | Volume in ml |
---|---|
13 | 144.5 |
14.5 | 162.8 |
16 | 183.3 |
17.5 | 202.4 |
19 | 211.2 |
20.5 | 227.8 |
22 | 247 |
Volume =_________ x+___________ where x is the grams of the unknown metal
grams | Volume in ml |
13 | 144.5 |
14.5 | 162.8 |
16 | 183.3 |
17.5 | 202.4 |
19 | 211.2 |
20.5 | 227.8 |
22 | 247 |
grams | volume(in ml) | grams*volume(in ml) | grams2 | volume(in ml)2 | |
13 | 144.5 | 1878.5 | 169 | 20880.25 | |
14.5 | 162.8 | 2360.6 | 210.25 | 26503.84 | |
16 | 183.3 | 2932.8 | 256 | 33598.89 | |
17.5 | 202.4 | 3542 | 306.25 | 40965.76 | |
19 | 211.2 | 4012.8 | 361 | 44605.44 | |
20.5 | 227.8 | 4669.9 | 420.25 | 51892.84 | |
22 | 247 | 5434 | 484 | 61009 | |
Sum = | 122.5 | 1379 | 24830.6 | 2206.75 |
279456.02 |
=122.5/7=17.5
=1379/7=197
=2206.75−122.52/7=63
=279456.02−13792/7=7793.02
=24830.6−122.5×1379/7=698.1
b===11.081
n==197−17.5×11.081=3.0833
Therefore, we find that the regression equation is:
volume(in ml) = 3.0833 + 11.081 grams
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