In: Operations Management
Given are data for two variables, x and y.
xi |
6 | 11 | 15 | 18 | 20 |
---|---|---|---|---|---|
yi |
5 | 9 | 12 | 19 | 30 |
(a) Develop an estimated regression equation for these data. (Round your numerical values to two decimal places.)
ŷ =
(b) Compute the residuals. (Round your answers to two decimal places.)
xi |
yi |
Residuals |
---|---|---|
6 | 5 | |
11 | 9 | |
15 | 12 | |
18 | 19 | |
20 | 30 |
(d) Compute the standardized residuals. (Round your answers to two decimal places.)
xi |
yi |
Standardized Residuals |
---|---|---|
6 | 5 | |
11 | 9 | |
15 | 12 | |
18 | 19 | |
20 | 30 |
Consider the following data for two variables, x and y.
xi |
135 | 110 | 130 | 145 | 175 | 160 | 120 |
---|---|---|---|---|---|---|---|
yi |
145 | 100 | 120 | 115 | 130 | 130 | 110 |
(a) Compute the standardized residuals for these data. (Round your answers to two decimal places.)
xi |
yi |
Standardized Residuals |
---|---|---|
135 | 145 | |
110 | 100 | |
130 | 120 | |
145 | 115 | |
175 | 130 | |
160 | 130 | |
120 | 110 |
The standardized residual with the largest absolute value is _____ .
1st question
a)
x-bar = 70/5 = 14
y-bar = 75/5 = 15
b = (sum(xy)-n*x-bar*y-bar)/(sum(x2)-n*x-bar^2) = (1251-5*14*15)/(1106-5*14^2) = 1.595238095 = 1.6 (Rounded to 2 decimal places)
a = y-ba-b*x-bar = 15-1.595238095*14 = -7.33333333 = -7.33(Rounded to 2 decimal places)
Formula
b)
xi | yi | Residual |
6 | 5 | 2.76 |
11 | 9 | -1.21 |
15 | 12 | -4.6 |
18 | 19 | -2.38 |
20 | 30 | 5.43 |
d)
xi | yi | Residual |
6 | 5 | 0.68 |
11 | 9 | -0.3 |
15 | 12 | -1.14 |
18 | 19 | -0.59 |
20 | 30 | 1.34 |