Question

In: Statistics and Probability

Question 1. A simple random sample survey of a large car dealership collects information on the...

Question 1. A simple random sample survey of a large car dealership collects information on the average hours worked and the average amount of commission collected by employees. There are 112 employees and the overall average number of hours worked is 21. The data table is given below.

Part i) Build a 95% percent confidence interval for the mean commission and the total commission

Part ii) Using ratio estimation, what should the minimum sample size be to be accurate to within 1 unit 19 times out of 20?

Data Table:

Unit Commission Hours_Worked
1 160 12
2 242 22
3 274 24
4 373 18
5 517 31
6 120 24
7 161 16
8 230 18
9 741 33
10 646 32
11 367 21
12 294 19
13 197 14
14 192 13
15 173 6
16 182 14
17 146 17
18 590 25
19 240 29
20 126 8
21 412 27
22 275 28
23 153 8
24 213 26
25 204 19
26 248 14
27 911 34
28 200 35
29 609 26
30 294 19
31 127 26
32 378 21
33 383 30
34 231 31
35 239 24
36 188 30
37 180 18
38 418 30

Solutions

Expert Solution

Calculating Mean Commission CI

Statistics

Variable N   N*   Mean   SE Mean   StDev   Variance   Minimum   Q1   Median   Q3   Maximum
Commission   38   0 306.2 30.0 185.2 34306.4 120.0   181.5   239.5   379.3   911.0

Step 1: start with

  • the number of observations n
  • the mean x
  • and the standard deviation s

Note: we should use the standard deviation of the entire population, but in many cases we won't know it.

We can use the standard deviation for the sample if we have enough observations (at least n=30, hopefully more).

Using our example:

  • number of observations n = 38
  • mean x = 306.2
  • standard deviation s = 185.2

Step 2: decide what Confidence Interval we want: 95% or 99% are common choices. Then find the "Z" value for that Confidence Interval here:

Confidence
Interval
Z
95% 1.960

For 95% the Z value is 1.960

Step 3: use that Z value in this formula for the Confidence Interval

x ± Zs√n

Where:

  • x is the mean of the mean commission
  • Z is the chosen Z-value from the table above
  • s is the standard deviation of the mean commission
  • n is the number of sample observations

And we have:

306.2 ± 1.960 × 185.2/√38

Which is:

306.2 ± 58.92

Calculating Total Commission CI

X ± ZS√N

Where:

  • X is the mean of the Total Commission
  • Z is the chosen Z-value from the table above
  • s is the standard deviation of the Total Commission
  • N is the number of obs

Using our example:

  • number of observations N = 112
  • mean X = 7579  
  • standard deviation S = 6697  

And we have:

7579 ± 1.960 × 6697/√112

Which is:

7579 ± 1240.654

Descriptive Statistics: total Commission
Statistics

Variable N   N*   Mean   SE Mean   StDev   Variance   Minimum   Q1   Median   Q3
total Commission   38   0   7579 1086   6697   44849551   1008   2850   5613   8735
Variable   Maximum
total Commission   30974
b. Ration Estimator



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