Question

In: Statistics and Probability

What is the critical for a large sample confidence interval for the mean with 98% confidence...

What is the critical for a large sample confidence interval for the mean with 98% confidence level?

Solutions

Expert Solution

For large sample we should use standard normal distribution to find the critical value for 98% confidence level.

=> significance level = 1 - 0.98 = 0.02

Using standard normal z-table we get z-score corresponding probability of 0.99 is, Zcrit = 2.33

Therefore, required critical values are -2.33, 2.33


Related Solutions

2.         a.         Find a 98% confidence interval for the true mean of a population if a sample of     ...
2.         a.         Find a 98% confidence interval for the true mean of a population if a sample of                  52 results in a mean of 100. Assume the population standard deviation is 12. b.        Assume now that the same results occurred, the population was normal, and the             sample size was reduced to 10. c.        Repeat problem 2b assuming that the population standard deviation was unknown, and              “s” was 12.
(a) How large a sample must be drawn so that a 98% confidence interval for μ...
(a) How large a sample must be drawn so that a 98% confidence interval for μ will have a margin of error equal to 3.8? Round the critical value to no less than three decimal places. Round the sample size up to the nearest integer. A sample size of __?is needed to be drawn in order to obtain a 98% confidence interval with a margin of error equal to 3.8. (b) If the required confidence level were 99.5%, would the...
The formula used to compute a large-sample confidence interval for p is p̂ ± (z critical...
The formula used to compute a large-sample confidence interval for p is p̂ ± (z critical value)   p̂(1 − p̂) n What is the appropriate z critical value for each of the following confidence levels? (Round your answers to two decimal places.) (a)    95%(b)    90%(c)    99%(d)    80%(e)    80%
A fitness center is interested in finding a 98% confidence interval for the mean number of...
A fitness center is interested in finding a 98% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 213 members were looked at and their mean number of visits per week was 3.5 and the standard deviation was 1.8. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean...
You are interested in finding a 98% confidence interval for the mean number of visits for...
You are interested in finding a 98% confidence interval for the mean number of visits for physical therapy patients. The data below show the number of visits for 14 randomly selected physical therapy patients. Round answers to 3 decimal places where possible. 5 24 21 21 15 25 23 12 7 6 9 20 19 19 a. To compute the confidence interval use a Z or T distribution? b. With 98% confidence the population mean number of visits per physical...
A fitness center is interested in finding a 98% confidence interval for the mean number of...
A fitness center is interested in finding a 98% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 251 members were looked at and their mean number of visits per week was 3.1 and the standard deviation was 2.8. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a Z or T distribution? b. With 98% confidence...
A fitness center is interested in finding a 98% confidence interval for the mean number of...
A fitness center is interested in finding a 98% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 213 members were looked at and their mean number of visits per week was 2.4 and the standard deviation was 1.8. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean...
A researcher is interested in finding a 98% confidence interval for the mean number of times...
A researcher is interested in finding a 98% confidence interval for the mean number of times per day that college students text. The study included 96 students who averaged 41.6 texts per day. The standard deviation was 13.3 texts.
A fitness center is interested in finding a 98% confidence interval for the mean number of...
A fitness center is interested in finding a 98% confidence interval for the mean number of days per week that Americans who are members of a fitness club go to their fitness center. Records of 257 members were looked at and their mean number of visits per week was 3.2 and the standard deviation was 1.8. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a distribution. b. With 98% confidence the population mean...
The mayor is interested in finding a 98% confidence interval for the mean number of pounds...
The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is generated in the city. The study included 240 residents whose mean number of pounds of trash generated per person per week was 34.5 pounds and the standard deviation was 7.8 pounds. Round answers to 3 decimal places where possible. a. To compute the confidence interval use a  z or t  distribution. b. With 98% confidence the population mean...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT