Question

Listed in the data table are amounts of​ strontium-90 (in​ millibecquerels, or​ mBq, per gram of​ calcium) in a simple random sample of baby teeth obtained from residents in two cities. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Use a 0.01 significance level to test the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater than the mean amount from city​ #2 residents. LOADING... Click the icon to view the data table of​ strontium-90 amounts. What are the null and alternative​ hypotheses? Assume that population 1 consists of amounts from city​ #1 levels and population 2 consists of amounts from city​ #2. A. Upper H 0​: mu 1less than or equalsmu 2 Upper H 1​: mu 1greater thanmu 2 B. Upper H 0​: mu 1not equalsmu 2 Upper H 1​: mu 1greater thanmu 2 C. Upper H 0​: mu 1equalsmu 2 Upper H 1​: mu 1not equalsmu 2 D. Upper H 0​: mu 1equalsmu 2 Upper H 1​: mu 1greater thanmu 2 The test statistic is nothing. ​(Round to two decimal places as​ needed.) The​ P-value is nothing. ​(Round to three decimal places as​ needed.) State the conclusion for the test. A. Fail to reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater. B. Fail to reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater. C. Reject the null hypothesis. There is not sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater. D. Reject the null hypothesis. There is sufficient evidence to support the claim that the mean amount of​ strontium-90 from city​ #1 residents is greater.

City_#1   City_#2
103   117
86   99
121   100
120   85
101   86
104   107
213   110
135   111
290   143
100   133
262   101
145   209

Answer 1