Question

Modify the previous program to use the Do-While Loop instead of the While Loop. This version of the program will ask the user if they wish to enter another name and accept a Y or N answer. Remove the "exit" requirement from before.

Output:

Enter the full name of a person that can serve as a reference: [user types: Bob Smith]

Bob Smith is reference #1
Would you like to enter another name (Y or N)? [user types: y]

Enter the full name of a person that can serve as a reference: [user types: Maria Garcia]

Maria Garcia is reference #2
Would you like to enter another name (Y or N)? [user types: N]

You have a total of 2 references

Notes and Hints:

1) You MUST use a DO-WHILE LOOP

2) You must accept the upper and lower case versions of Y and N in the user's reply

3) Hint: That function you used in the previous problem with have a small issue here. That is because there is a newline (Enter) in the keyboard buffer after the user types Y or N. Do you remember how we ignored that extra newline in Chp 3?

Starter Code:

// VARIABLES

// INPUT AND LOOP

std::cout << "Enter the full name of a person that can serve as a reference: ";
  
std::cout << std::endl; // For Mimir
  
std::cout << name << " is reference #" << YOUR_CODE << std::endl;
std::cout << "Would you like to enter another name (Y or N)? ";
  
std::cout << std::endl; // For Mimir

  
// OUTPUT FOR COUNTER
std::cout << std::endl; // So that final line looks nice
std::cout << "You have a total of " <

Previous pogram:

#include<iostream>

using namespace std;

int main()
{
string str;
int refcount=0;

cout<<"Enter the full name of a person that can serve as a reference (type 'exit' to quit): "<<endl;
getline(cin,str);

if(str.compare("exit")==0)
{
refcount=0;
}
else
{
while(str.compare("exit")!=0)
{
refcount++;
cout<<str<<" is reference #"<<refcount<<endl;
cout<< "Enter the name of another person that can serve as a reference (type 'exit' to quit): "<<endl;
getline(cin,str);
  
}

  
}

cout<<"\n\n"<<"You have a total of "<<refcount<<" references\n"<< endl;
return 0;
}

Answer 1

** Compiled in Dev cpp**

CODE:

#include<iostream>

using namespace std;

int main()
{
        string str;
        char choice;
        int refcount=0;
        
        /*
        Unlike for and while loops, which test the loop condition at the top of the loop, 
        the do...while loop checks its condition at the bottom of the loop.
        A do...while loop is similar to a while loop, 
        except the fact that it is guaranteed to execute at least one time.
        */
        do
        {               
                cout << "Enter the full name of a person that can serve as a reference: " << endl;  
                // cin.ignore() is used to ignore the extra newline.
                cin.ignore();
                // reading the name using getline().    
                getline(cin, str);
                // incrementing the refcount.
                refcount++;
                cout << str << " is reference #" << refcount << endl;
                cout << "Would you like to enter another name (Y or N)? " << endl;
                // reading the choice.
                cin >> choice;
        }
        // This loop repeats if the choice is either Y or y.
        while(choice == 'Y' || choice == 'y');
                
        cout<< "\n\n" << "You have a total of " << refcount << " references\n" << endl;
        return 0;
}

Screenshots:

refer this to know the proper indentations.

Sample I/O: