In: Statistics and Probability
The mean output of a certain type of amplifier is 204 watts with a variance of 100.
If 53 amplifiers are sampled, what is the probability that the mean of the sample would be less than 207.9 watts? Round your answer to four decimal places.
Solution :
mean = = 204
standard deviation = = 100 = 10
n = 53
= = 204
= / n = 10 / 53 = 1.3736
P( < 207.9 ) = P(( - ) / < (207.9 -204) /1.3736 )
= P(z < 2.84 )
= 0.9977
probability = 0.9977