In: Statistics and Probability
Heights of fences are normally distributed with a mean of 52 inches and a standard deviation of 4 inches.
1. Find the probability that one randomly selected fence is under
54 inches.
2. Find the probability that two randomly selected fences are both under 54 inches.
3. Find the probability that the mean height of 4 randomly
selected fences is under 54 inches.
Solution :
Given that ,
1) P(x < 54)
= P[(x - ) / < (54 - 52) / 4 ]
= P(z < 0.5)
Using z table,
= 0.6915
2) Given that ,
= 52
= / n = 4/ 2 = 2.83
P( < 54) = P(( - ) / < (54 - 52) / 2.83)
= P(z < 0.71)
Using z table
= 0.7611
3) Given that ,
= 52
= / n = 4/ 4 = 2
P( < 54) = P(( - ) / < (54 - 52) / 2)
= P(z < 0.71)
Using z table
= 0.9772