In: Statistics and Probability
The monthly incomes of 14 randomly selected individuals who have recently graduated with a? bachelor's degree in economics have a sample standard deviation of $344.
Construct a confidence interval for the population variance
?2 and the population standard deviation ?.
Use a 99% level of confidence. Assume the sample is from a normally distributed population.
What is the confidence interval for the population variance ?2??
the formula for confidence interval for the variance is
where
n = 14
s = 344
= 29.82 with degree of freedom = n-1 = 14-13
= 3.57 with degree of freedom = n-1 = 14-13
setting the given values in the above formula, we get
=
So, the 99% confidence interval for the population variance is (51588.46, 430915.41)