How many moles of NH3 (Kb= 1.8 × 10‒5) must be dissolved in water in order...

How many moles of NH3 (Kb= 1.8 × 10‒5) must be dissolved in water in order to prepare 0.616 L of solution with a pH of 11.22?

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queen_honey_blossom answered 1 year ago

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Take 12.5 mL of 0.200 moles of aqueous Ammonia (NH3), whose Kb = 1.8 x 10-5,...

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Question

How many moles of NH3 (Kb= 1.8 × 10‒5) must be dissolved in water in order...

Solutions

Expert Solution

Related Solutions

Take 12.5 mL of 0.200 moles of aqueous Ammonia (NH3), whose Kb = 1.8 x 10-5,...

Given that Ka for HCN is 4.9×10−10 and Kb for NH3 is 1.8×10−5 , calculate Kb...

In a titration of a 250mL solution of 0.05M ammonia (NH3) (Kb=1.8 * 10^-5) with a...

A buffer is made by combining 5.55 g of NH3 (Kb = 1.8 X 10-5) with...

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts...

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts...

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts...

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts...

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts...

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts...