In: Statistics and Probability
Consider the following sample information for three treatment groups:
| Treatment 1 | Treatment 2 | Treatment 3 | 
| 15 | 18 | 11 | 
| 18 | 21 | 12 | 
| 13 | 17 | 15 | 
| 12 | 15 | 9 | 
(a) using the 0.05 significance level, test the null hypothesis that the three treatment means are equal
(b) Interpret your results.
PLEASE SHOW WORK! IM TRYING TO LEARN!!!!
Data:

Excel Output :

( To get Excel output type data on excel sheet then select Data > Data Analysis > one way Anova > Input range : select all data , Grouped by column then select Ok )
Hypothesis :
  
(all means are same)
Ha : at least on eof the mean 
 is
different .
Test statistics
F = 5.55
P value : 0.02688
alpha (significance level ) =0.05 (given)
Interpretation:
Decision using p value :
If p value (0.02688) < 0.05 hence we fails to reject H0.
Conclusion we have enough evidence to conclude that at least on of treatment is not same.
Decision using critical value
F critical value = 4.256
F (5.55) > F critical value (4.256) therefore we reject H0.
we get same result using P value and F critical