In: Statistics and Probability
Listed below are the top 10 annual salaries (in millions of dollars) of TV personalities. Find the range, variance, and standard deviation for the sample data. Given that these are the top 10 salaries, do we know anything about the variation of salaries of TV personalities in general?
38 37 36 29 19 15 13 9 8.9 7.4
The range of the sample data is $ __ million. (Type an integer or a decimal.)
The variance of the sample data is __. (Round to two decimal places as needed.)
The standard deviation of the sample data is $ __ million. (Round to two decimal places as needed.)
Is the standard deviation of the sample a good estimate of the variation of salaries of TV personalities in general?
A. No, because the sample is not representative of the whole population.
B. Yes, because the sample is random.
C. No, because there is an outlier in the sample data.
D. Yes, because the standard deviation is an unbiased estimator.
First we arrange the observation in incresing order
7.4,8.9,9,13,15,19,29,36,37,38
Range = L -S
Where L=largest value and S=smallest value
x |
(x-) |
(x-)^2 |
||
7.4 |
21.23 |
-13.83 |
191.2689 |
|
8.9 |
21.23 |
-12.33 |
152.0289 |
|
9 |
21.23 |
-12.23 |
149.5729 |
|
13 |
21.23 |
-8.23 |
67.7329 |
|
15 |
21.23 |
-6.23 |
38.8129 |
|
19 |
21.23 |
-2.23 |
4.9729 |
|
29 |
21.23 |
7.77 |
60.3729 |
|
36 |
21.23 |
14.77 |
218.1529 |
|
37 |
21.23 |
15.77 |
248.6929 |
|
38 |
21.23 |
16.77 |
281.2329 |
|
Total |
212.3 |
1412.841 |
variance =
standard deviation =
The range of the sample data is $ 30.6 million.
The variance of the sample data is 156.98
The standard deviation of the sample data is $ 12.53 million.
A. No, because the sample is not representative of the whole population.